2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
The reaction is:
KOH + HCl = KCl + H2O
The answer is 5 moles KCl.
The reaction is:
2 KClO3 = 2 KCl + 3 O2
38,4 moles of oxygen are produced.
Potassium chlorate = KClO3
Decompostion: 2KClO3 ==> 3O2 + 2KCl
7.5 moles KClO3 x 3 mole O2/2 moles KClO3 = 11.25 moles O2
Balanced equation: 2KClO3 --> 2KCl + 3O2
6 mol KClO3 = 3 x 2 mol KCl, so the number of moles O2 that can be produced by 6 mol KClO3 is:
3 x 3 mol O2 = 9 mol O2.
0,0835 moles
11,25 moles of oxygen are produced.
8,55 moles of oxygen are produced.
Nothing is produced, 500g potassium chlorate will be the same 500 g potassium chlorate after reaction. Actually there is no reaction at all.
Oxygen gas is produced. The hydrogen peroxide will decompose to give water and oxygen, potassium Iodide is acting as a catalyst 2H2O2(l) ------> 2H2O(l) + O2(g)
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
On a safety match (the kind you strike on a box) the red bit is primarily a compound called potassium chlorate. The strip on the box is red phosphorous. When you strike it on the box the two compounds create an explosive mixture which is then ignited by the heat and sparks produced by friction between the strip and the match head. Strike anywhere matches put the two compounds together on the match, the red is the phosphorous and the white tip is potassium chlorate. When you strike the match they mix and catch fire similar to striking a safety match on the box.
Nothing is produced, 500g potassium chlorate will be the same 500 g potassium chlorate after reaction. Actually there is no reaction at all.
I Don't knows Sorry
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
Oxygen gas is produced. The hydrogen peroxide will decompose to give water and oxygen, potassium Iodide is acting as a catalyst 2H2O2(l) ------> 2H2O(l) + O2(g)
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
yes
Equation: 2KClO3 + Cl2 ---> 2KCl + 3O2 + Cl2 1. Solve for the number of moles of KClO3 in 36.3 g. (.2962 molKClO3) 2. Multiply that value by (3/2), from the equation's coefficients. (.4447 molO2) Note: A BCA table could also be used. 3. Solve for the mass of .4447 molO2. 14.2 grams of oxygen would be produced.
A 1.80-gram mixture of potassium chlorate, kclo3, and potassium chloride, kcl, was heated until all of the kclo3 had decomposed the liberated oxygen, after drying, occupied 405 ml at 25C when the barometric pressure was 745 torr. This is the problem and the questions were... a. How many moles of O2 were produced? b. What percent of the mixture was KClO3? KCl? Please help!!
On a safety match (the kind you strike on a box) the red bit is primarily a compound called potassium chlorate. The strip on the box is red phosphorous. When you strike it on the box the two compounds create an explosive mixture which is then ignited by the heat and sparks produced by friction between the strip and the match head. Strike anywhere matches put the two compounds together on the match, the red is the phosphorous and the white tip is potassium chlorate. When you strike the match they mix and catch fire similar to striking a safety match on the box.
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
there are two moles produced in potassium nitrate.