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How many moles of water are formed when 15 mL of 0.40 M LiOH is added to 25 mL of 0.60 M H2SO4?
Wiki User
∙ 10y ago
The value is o,oo6 moles water.
Wiki User
∙ 10y ago
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When lithium hydroxide pellets are added to a solution of sulfuric acid what is formed?
When lithium hydroxide pellets are added to a solution of sulfuric acid, lithium sulfate and water are formed. The reaction can be represented by the chemical equation: LiOH + H2SO4 → Li2SO4 + 2H2O.
What happens when sulfur trioxide reacts with water?
H2SO4 is formed
What is the balance between k and h2so4?
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
How many moles of which reactant are in excess when 359.0 mL of 0.259 M sulfuric acid reacts with 0.510 L of 0.191 M sodium hydroxide to form water and aqueous sodium sulfate?
To determine the limiting reactant, we first need to convert the volumes of the solutions to moles using the formula moles = Molarity x Volume (L). Once we have the moles of each reactant, we can compare them based on the stoichiometry of the balanced equation to identify the limiting reactant. The reactant with excess moles will be the one not completely consumed in the reaction.
What salt is formed when sulfuric acid plus potassium hydroxide are mixed?
Actually there are two possibillities:K2SO4, potassium sulfate, when 1 mole sulfuric acid is added to 2 moles potassium hydroxide 2 KOH + H2SO4 ------> K2SO4 + 2 H2OorKHSO4, potassium hydrogen sulfate (-bisulfate), when 1 mole sulfuric acid is added to 1 mole potassium hydroxide 1 KOH + H2SO4 ------> KHSO4 + H2O
How many moles of H2SO4 are produced from 13 moles of H2O?
Sulfuric acid is not obtained from water.
How many moles of which reactant are in excess when 359.0 mL of 0.259 M sulfuric acid reacts with 0.510 L of 0.191 M sodium hydroxide to form water and aqueous sodium sulfate?
To determine the limiting reactant, we first need to convert the volumes of the solutions to moles using the formula moles = Molarity x Volume (L). Once we have the moles of each reactant, we can compare them based on the stoichiometry of the balanced equation to identify the limiting reactant. The reactant with excess moles will be the one not completely consumed in the reaction.
When lithium hydroxide pellets are added to a solution of sulfuric acid what is formed?
When lithium hydroxide pellets are added to a solution of sulfuric acid, lithium sulfate and water are formed. The reaction can be represented by the chemical equation: LiOH + H2SO4 → Li2SO4 + 2H2O.
What happens when sulfur trioxide reacts with water?
H2SO4 is formed
How many moles of water are formed with 230 moles of H2 and 110 moles of O2?
For the reaction 2H₂ + O₂ → 2H₂O, the stoichiometry shows that 2 moles of H₂ are needed to react with 1 mole of O₂ to form 2 moles of H₂O. Therefore, with 230 moles of H₂ and 110 moles of O₂, both reactants are in excess so all the O₂ will be used up. This means 110 moles of O₂ will react with 220 moles of H₂ to form 220 moles of H₂O.
How many moles of H2O are produced when 1 mole of MgOH2 reacts with 1 mole of H2SO4?
The balanced chemical equation for the reaction between magnesium hydroxide (Mg(OH)2) and sulfuric acid (H2SO4) is: Mg(OH)2 + H2SO4 -> MgSO4 + 2H2O. From the equation, 1 mole of Mg(OH)2 will produce 2 moles of water (H2O) when it reacts with 1 mole of H2SO4.
According to the following balanced reaction how many moles of NO are formed from 8.44 moles of NO2 if there is plenty of water present?
Balanced equation. 3NO2 + H2O -> 2HNO3 + NO 8.44 moles NO2 (1 mole NO/3 moles NO2) = 2.81 moles NO formed
How many moles of water form when 5.5 moles of oxygen reacts?
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
A biochemist wishes to dilute 75 ml of an aqueous 3.5 M H2SO4 solution to an aqueous 2 M H2SO4 solution. How much water should be added to the solution?
To dilute the 3.5 M H2SO4 solution to 2 M, you need to add water. Use the formula M1V1 = M2V2, where M represents molarity and V represent volume. For this situation, you'll end up adding 75 ml of water to the initial 75 ml of 3.5 M H2SO4 solution to achieve a final 2 M concentration.
How do you prepare 2N H2SO4 and 2M H2SO4?
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
If 5.0 moles of C3H8 react how many molecules of water are formed?
1.2x10^25
Which salt is produced when sulfuric acid and calcium hydroxide react completely?
H2SO4 + Ca(OH)2 --> CaSO4 + 2H2O Balance the equation by putting a 2 in front of H2O. Sulphuric acid added to Calcium Hydroxide will form Calcium Sulphate along with water. This is an example of neutralisation reaction where an acid is added to a base, forming a salt and a by product of water.
