2H2 + O2 --> 2H2O
As you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
0.29M = 0.29 moles in 1000 ml so 0.29 x 110/1000 = 0.0319 moles
moles HA in excess = 0.002 - 0.001 = 0.001moles A- formed = 0.001pKa = 8pH = 8 + log 0.001/0.001 = 8
Aside from a few of the ultra-high-molecular-weight polymers I can't imagine a single molecule that had a mole of anything in it. But since you asked... 1. Figure out how many grams a mole of the compound weighs. Easy one: a mole of water weighs 18 grams - two grams worth of hydrogen, 16 grams of oxygen. 2. Now determine the mass of the sample you have. Our sample has a mass of 990 grams - our sample is a liter of distilled water that we took 10 ml from to make the math easier. 990 grams of water is 55 moles. 3. Multiply the number of moles you have by the number of each atom in the compound. Here we have 110 moles of hydrogen atoms (or 55 moles of H2 molecules) and 55 moles of oxygen atoms (or 27.5 moles of O2 molecules).
110 g.
110 g/l
0.29M = 0.29 moles in 1000 ml so 0.29 x 110/1000 = 0.0319 moles
moles HA in excess = 0.002 - 0.001 = 0.001moles A- formed = 0.001pKa = 8pH = 8 + log 0.001/0.001 = 8
The volume is 4908 L at oC.
the Atomic Mass of FeS2 is 110. You cannot find the no. of moles in a mole of FeS2 coz it is only a mole.
the atomic mass of FeS2 is 110. You cannot find the no. of moles in a mole of FeS2 coz it is only a mole.
0.035mol. Apply to PV=nRT
110.Improved Answer:-It is 4
That is 3.88 ounces of water
110 miles
516 grams of water is approximately 110 teaspoons.
about 100-110
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.