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How many grams are in 1 mole of NaNO3?
The molar mass of NaNO3 is 85.0 g/mol. Therefore, 1 mole of NaNO3 is equal to 85.0 grams.
How much KCl will remain undissolved if 500 grams is mixed in a liter of pure water at 40 degree celsius?
At 40 degrees Celsius, the solubility of KCl in water is approximately 34 grams per 100 grams of water. Therefore, in a liter of pure water at 40 degrees Celsius, 340 grams of KCl can dissolve. If 500 grams of KCl is added, 160 grams will remain undissolved since 500 grams - 340 grams = 160 grams.
What is the mass in grams of 0.254 mol sodium nitrate?
To find the mass in grams of 0.254 mol of sodium nitrate (NaNO3), you would multiply the number of moles by the molar mass of NaNO3. The molar mass of NaNO3 is 85 grams/mol. So, 0.254 mol x 85 g/mol = 21.59 grams of sodium nitrate.
What is the solubility of sodium nitrate NaNO3 in water that is at 90C?
The solubility of sodium nitrate NaNO3 in water at 90°C is approximately 180 grams per 100 grams of water.
How many grams of nano3 will precipitate if a saturated solution of nano3 in 200g H2O at 50c is cooled to 20c?
You need to find a graph of solubility in your textbook. It should have temperature on the x-axis and "grams dissolved per 100 grams H2O" on the y-axis (or some such.) Sodium nitrate is less soluble in cool water than warm. Use the graph to determine how many grams are dissolved at 50°C, multiplying by 2 since there are 200 grams H2O. Then determine how many grams are dissolved at 20°C, again multiplying by 2. Subtract the two numbers to find the grams that will precipitate
How many grams are in 1 mole of NaNO3?
The molar mass of NaNO3 is 85.0 g/mol. Therefore, 1 mole of NaNO3 is equal to 85.0 grams.
How much KCl will remain undissolved if 500 grams is mixed in a liter of pure water at 40 degree celsius?
At 40 degrees Celsius, the solubility of KCl in water is approximately 34 grams per 100 grams of water. Therefore, in a liter of pure water at 40 degrees Celsius, 340 grams of KCl can dissolve. If 500 grams of KCl is added, 160 grams will remain undissolved since 500 grams - 340 grams = 160 grams.
How many moles of nitrogen N are in 60.0 g of nitrous oxide N2O?
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
What is the density of glycerin at 13 degree Celsius?
The density of glycerin at 13 degrees Celsius is approximately 1.261 grams per cubic centimeter.
What is the percent concentration by mass of a solution 4.2g of NaNO3 in 60 g water?
4.2 grams NaNO3/60 grams water * 100 = 7% by mass -------------------
Is degree celsius a unit of mass?
Because every object has mass but the metric unit of measure is grams
What is the mass in grams of 0.254 mol sodium nitrate?
To find the mass in grams of 0.254 mol of sodium nitrate (NaNO3), you would multiply the number of moles by the molar mass of NaNO3. The molar mass of NaNO3 is 85 grams/mol. So, 0.254 mol x 85 g/mol = 21.59 grams of sodium nitrate.
What is the solubility of sodium nitrate NaNO3 in water that is at 90C?
The solubility of sodium nitrate NaNO3 in water at 90°C is approximately 180 grams per 100 grams of water.
What is the density of ice at -10 degree Celsius?
The density of ice at -10 degrees Celsius is approximately 0.917 grams per cubic centimeter.
Could you convert .10 mol of NaNO3 to grams?
To convert 0.10 mol of NaNO3 to grams, you need to use the molar mass of NaNO3, which is 85 g/mol. Multiplying 0.10 mol by the molar mass will give you the answer: 0.10 mol x 85 g/mol = 8.5 grams of NaNO3.
How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
How many grams of nano3 will precipitate if a saturated solution of nano3 in 200g H2O at 50c is cooled to 20c?
You need to find a graph of solubility in your textbook. It should have temperature on the x-axis and "grams dissolved per 100 grams H2O" on the y-axis (or some such.) Sodium nitrate is less soluble in cool water than warm. Use the graph to determine how many grams are dissolved at 50°C, multiplying by 2 since there are 200 grams H2O. Then determine how many grams are dissolved at 20°C, again multiplying by 2. Subtract the two numbers to find the grams that will precipitate
