The molar mass of NaNO3 is 84.9947 g/mol. Multiplying by 0.254 mol gives 21.5886538 g, or correctly sigFig'd, 21.6 g
The molecular mass of sodium nitrate is 84,9947.
Using atomic weights for Na = 23 and N=14 and O = 16, one arrives at a mass for 1 mole of NaNO3 of23 + 14 + (3x16) = 85 grams/mole
The solubility of sodium nitrate at 20°C is 88 g/100 g water. To find the mass of sodium nitrate that can dissolve in water at this temperature, you would need to provide the amount of water in the solution. The mass of sodium nitrate that can dissolve would depend on the total mass of the solution.
The molar mass of sodium is approximately 23 grams per mole.
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
The molecular mass of sodium nitrate is 84,9947.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
To find the mass of 6.0 moles of sodium nitrate (NaNO3), you first need to calculate the molar mass of NaNO3, which is 85.00 g/mol. Then, you multiply the molar mass by the number of moles: 85.00 g/mol x 6.0 mol = 510.0 g. Therefore, the mass of 6.0 moles of sodium nitrate is 510.0 grams.
Using atomic weights for Na = 23 and N=14 and O = 16, one arrives at a mass for 1 mole of NaNO3 of23 + 14 + (3x16) = 85 grams/mole
Sodium nitrate is NaNO3. The percent nitrate is given by :PCT Nitrate = [ ( 14 + 48 ) / ( 23 + 14 + 48 ) ][ 100 ] = [ 62 /85 ][ 100 ] = 72.94 mass percent
The solubility of sodium nitrate at 20°C is 88 g/100 g water. To find the mass of sodium nitrate that can dissolve in water at this temperature, you would need to provide the amount of water in the solution. The mass of sodium nitrate that can dissolve would depend on the total mass of the solution.
To find the number of moles in 1.25 grams of iron nitrate, we need to know its molar mass. Iron nitrate has a molar mass of approximately 404.0 g/mol. By dividing the mass by the molar mass, we find that 1.25 grams of iron nitrate is roughly 0.0031 moles.
The molar mass of sodium is approximately 23 grams per mole.
To find the number of moles in 120 grams of sodium, divide the given mass by the molar mass of sodium. The molar mass of sodium is approximately 23 grams per mole. Therefore, 120 grams of sodium is equal to 120/23 ≈ 5.22 moles of sodium.
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.
The mass of silver nitrate is 30,6 g.