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How many MOLES of sodium nitrate are present in 2.85 grams of this compound?
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
Which weighs more 5moles of sodium nitrate or 4 moles of carbon dioxide?
I'm assuming that your instructor is using the terms mass and weight interchangeably. First determine the molar mass of each compound by multiplying the molar mass of each element by its subscript and add them together. The molar mass of an element is its atomic weight on the periodic table in grams. Molar mass of sodium nitrate (NaNO3) (1 atom Na x 22.98970g/mol Na) + (1 atom N x 14.0067g/mol N) + (3 atoms O x 15.9994g/mol O) = 84.9946g/mol NaNO3 Molar mass of carbon dioxide (CO2) (1 atom C x 12.0107g/mol C) + (2 atoms O x 15.9994g/mol O) = 44.0095g/mol CO2 Now multiply the molar mass for each compound by the number given and compare the results to determine which has the greater mass. 5mol NaNO3 x 84.9946g/mol NaNO3 = 424.973g NaNO3 4 mol CO2 x 44.0095g/mol CO2 = 176.038 So 5 moles of sodium nitrate has a mass greater than 4 moles of carbon dioxide.
What is the percentage by mass of nitrogen in sodium nitrate?
The formula for sodium nitrate is NaNO3, showing that each formula unit contains one sodium atom, one nitrogen atom, and three oxygen atoms. The gram atomic masses of sodium, nitrogen, and oxygen are 22.9898, 14.0067, and 15.9994 respectively. Therefore, the percentage by mass of nitrogen in the compound is: 100{14.0067/[14.0067 + 22.9898 + 3(15.9994)]} or about 16.4795, to the justified number of significant digits.
How many moles in 1.25 grams of iron nitrate?
To find the number of moles in 1.25 grams of iron nitrate, we need to know its molar mass. Iron nitrate has a molar mass of approximately 404.0 g/mol. By dividing the mass by the molar mass, we find that 1.25 grams of iron nitrate is roughly 0.0031 moles.
How many moles is 8.0g of ammonium nitrate?
To find the number of moles in 8.0g of ammonium nitrate, you need to divide the given mass by the molar mass of the compound. The molar mass of ammonium nitrate (NH4NO3) is 80.04 g/mol. Therefore, 8.0g ÷ 80.04 g/mol = 0.1 moles of ammonium nitrate.
How many MOLES of sodium nitrate are present in 2.85 grams of this compound?
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
What is the mass in grams of 0.254 mol sodium nitrate?
To find the mass in grams of 0.254 mol of sodium nitrate (NaNO3), you would multiply the number of moles by the molar mass of NaNO3. The molar mass of NaNO3 is 85 grams/mol. So, 0.254 mol x 85 g/mol = 21.59 grams of sodium nitrate.
What is the molecular mass of sodium nitrate?
The molecular mass of sodium nitrate is 84,9947.
What is the mass of 1 mol of NaNO3?
Using atomic weights for Na = 23 and N=14 and O = 16, one arrives at a mass for 1 mole of NaNO3 of23 + 14 + (3x16) = 85 grams/mole
What is the percentage of oxygen in sodium nitrate(NaNO3)?
The percentage of oxygen in sodium nitrate (NaNO3) is 53.9%. This is calculated by dividing the molar mass of oxygen in the compound by the molar mass of the entire compound and then multiplying by 100.
What is the percentage by mass of nitrate in sodium nitrate?
Sodium nitrate is NaNO3. The percent nitrate is given by :PCT Nitrate = [ ( 14 + 48 ) / ( 23 + 14 + 48 ) ][ 100 ] = [ 62 /85 ][ 100 ] = 72.94 mass percent
Which weighs more 5moles of sodium nitrate or 4 moles of carbon dioxide?
I'm assuming that your instructor is using the terms mass and weight interchangeably. First determine the molar mass of each compound by multiplying the molar mass of each element by its subscript and add them together. The molar mass of an element is its atomic weight on the periodic table in grams. Molar mass of sodium nitrate (NaNO3) (1 atom Na x 22.98970g/mol Na) + (1 atom N x 14.0067g/mol N) + (3 atoms O x 15.9994g/mol O) = 84.9946g/mol NaNO3 Molar mass of carbon dioxide (CO2) (1 atom C x 12.0107g/mol C) + (2 atoms O x 15.9994g/mol O) = 44.0095g/mol CO2 Now multiply the molar mass for each compound by the number given and compare the results to determine which has the greater mass. 5mol NaNO3 x 84.9946g/mol NaNO3 = 424.973g NaNO3 4 mol CO2 x 44.0095g/mol CO2 = 176.038 So 5 moles of sodium nitrate has a mass greater than 4 moles of carbon dioxide.
What is the percentage by mass of nitrogen in sodium nitrate?
The formula for sodium nitrate is NaNO3, showing that each formula unit contains one sodium atom, one nitrogen atom, and three oxygen atoms. The gram atomic masses of sodium, nitrogen, and oxygen are 22.9898, 14.0067, and 15.9994 respectively. Therefore, the percentage by mass of nitrogen in the compound is: 100{14.0067/[14.0067 + 22.9898 + 3(15.9994)]} or about 16.4795, to the justified number of significant digits.
How do you Calculate how much sodium nitrate is needed to give 126g of nitric acid by reaction?
The reaction would be NaNO3 (s) + H2SO4 (l) -> HNO3 (l) + NaHSO4 (s)Moles ratio 1 : 1 : 1 : 1Moles of nitric acid:= Mass / Mr= 126g / HNO3= 126g / (1) + (14) + (16 x 3)= 126g / (1) + (14) + (48)= 126g / 63= 2 molsodium nitrate:nitric acidMoles ratio 1 : 1Actual moles in reaction 2 : 2Mass of sodium nitrate:= Moles x Mr= 2 x NaNO3= 2 x (23) + (14) + (16 x 3)= 2 x (23) + (14) + (48)= 2 x 85= 170gMass of sodium nitrate needed = 170g
How many formula units would there be in a 54.3 gram sample of sodium nitrate?
To determine the number of formula units in a sample of a compound, you first need to calculate the molar mass of the compound. Sodium nitrate has a molar mass of 85 grams/mol. Next, you convert the given mass of the sample (54.3 grams) to moles by dividing by the molar mass. This gives you approximately 0.639 moles of sodium nitrate. Since one mole of a compound contains Avogadro's number of formula units (6.022 x 10^23), the 54.3 gram sample of sodium nitrate would contain approximately 3.85 x 10^23 formula units.
How many moles of nitrogen N are in 60.0 g of nitrous oxide N2O?
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
Could you convert .10 mol of NaNO3 to grams?
To convert 0.10 mol of NaNO3 to grams, you need to use the molar mass of NaNO3, which is 85 g/mol. Multiplying 0.10 mol by the molar mass will give you the answer: 0.10 mol x 85 g/mol = 8.5 grams of NaNO3.
