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The formula for sodium nitrate is NaNO3, showing that each formula unit contains one sodium atom, one nitrogen atom, and three oxygen atoms. The gram atomic masses of sodium, nitrogen, and oxygen are 22.9898, 14.0067, and 15.9994 respectively. Therefore, the percentage by mass of nitrogen in the compound is:
100{14.0067/[14.0067 + 22.9898 + 3(15.9994)]} or about 16.4795, to the justified number of significant digits.
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What is the percentage by mass of nitrogen in ammonium nitrate?
# of AtomsAt Wt.Total Wt.Nitrogen214.006728.0134Hydrogen41.007944.03176Oxygen315.999447.9982Total Molecular weight80.04% of Nitrogen=28.01/80.04 = 35%
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
The percent by mass of nitrogen in NH4NO3 is closest to?
Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%
What is the mass percentage of nitrogen in ammonia?
The mass percentage of nitrogen in ammonia (NH3) is 82.35%. This is calculated by dividing the mass of nitrogen in one mole of ammonia by the molar mass of ammonia, and then multiplying by 100 to get the percentage.
What is the mass of 6.0 moles of sodium nitrate (NaNO3)?
To find the mass of 6.0 moles of sodium nitrate (NaNO3), you first need to calculate the molar mass of NaNO3, which is 85.00 g/mol. Then, you multiply the molar mass by the number of moles: 85.00 g/mol x 6.0 mol = 510.0 g. Therefore, the mass of 6.0 moles of sodium nitrate is 510.0 grams.
What percentage by mass of nitrogen is in aluminum nitrate?
The molar mass of aluminum nitrate (Al(NO3)3) is 213 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. Therefore, the percentage by mass of nitrogen in aluminum nitrate is (3 * 14) / 213 * 100 ≈ 19.7%.
What is the percentage by mass of nitrogen in ammonium nitrate?
# of AtomsAt Wt.Total Wt.Nitrogen214.006728.0134Hydrogen41.007944.03176Oxygen315.999447.9982Total Molecular weight80.04% of Nitrogen=28.01/80.04 = 35%
What is the percentage of nitrogen by mass in calcium nitrate?
The molar mass of calcium nitrate is 164.1 g/mol. The molar mass of nitrogen is 14.01 g/mol. So, the percentage of nitrogen in calcium nitrate is (14.01 g/mol / 164.1 g/mol) * 100% ≈ 8.54%.
What is the percentage by mass of nitrate in sodium nitrate?
Sodium nitrate is NaNO3. The percent nitrate is given by :PCT Nitrate = [ ( 14 + 48 ) / ( 23 + 14 + 48 ) ][ 100 ] = [ 62 /85 ][ 100 ] = 72.94 mass percent
What is the percentage of oxygen in sodium nitrate(NaNO3)?
The percentage of oxygen in sodium nitrate (NaNO3) is 53.9%. This is calculated by dividing the molar mass of oxygen in the compound by the molar mass of the entire compound and then multiplying by 100.
What is the molecular mass of sodium nitrate?
The molecular mass of sodium nitrate is 84,9947.
What is the mass of sodium nitrate at 20 degree Celsius when ya solubility is 880?
The solubility of sodium nitrate at 20°C is 88 g/100 g water. To find the mass of sodium nitrate that can dissolve in water at this temperature, you would need to provide the amount of water in the solution. The mass of sodium nitrate that can dissolve would depend on the total mass of the solution.
What is the mass of the nitrogen atoms in one mole of cadmium nitrate?
To find the mass of the nitrogen atoms in one mole of cadmium nitrate, calculate the molar mass of cadmium nitrate (Cd(NO3)2) and then multiply it by the number of nitrogen atoms in one mole of cadmium nitrate (2 nitrogen atoms). The molar mass of cadmium nitrate is 236.41 g/mol. Therefore, the mass of the nitrogen atoms in one mole of cadmium nitrate is 28.02 g.
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
The percent by mass of nitrogen in NH4NO3 is closest to?
Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%
What Maximum percentage of nitrogen by mass?
The maximum percentage of nitrogen by mass is about 78.08%, which is the composition of nitrogen gas (N2) in the atmosphere.
What is the mass percentage of nitrogen in ammonia?
The mass percentage of nitrogen in ammonia (NH3) is 82.35%. This is calculated by dividing the mass of nitrogen in one mole of ammonia by the molar mass of ammonia, and then multiplying by 100 to get the percentage.
