The molar mass of calcium nitrate is 164.1 g/mol. The molar mass of nitrogen is 14.01 g/mol. So, the percentage of nitrogen in calcium nitrate is (14.01 g/mol / 164.1 g/mol) * 100% ≈ 8.54%.
The molar mass of aluminum nitrate (Al(NO3)3) is 213 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. Therefore, the percentage by mass of nitrogen in aluminum nitrate is (3 * 14) / 213 * 100 ≈ 19.7%.
To find the mass of the nitrogen atoms in one mole of cadmium nitrate, calculate the molar mass of cadmium nitrate (Cd(NO3)2) and then multiply it by the number of nitrogen atoms in one mole of cadmium nitrate (2 nitrogen atoms). The molar mass of cadmium nitrate is 236.41 g/mol. Therefore, the mass of the nitrogen atoms in one mole of cadmium nitrate is 28.02 g.
The molar mass of calcium nitrate is 164.1 g/mol. This is equivalent to 164,100 mg/mol.
The maximum percentage of nitrogen by mass is about 78.08%, which is the composition of nitrogen gas (N2) in the atmosphere.
The percentage of nitrogen in N2O4 is 63.6%. This is determined by dividing the molar mass of nitrogen in N2O4 by the molar mass of the compound and then multiplying by 100.
The molar mass of aluminum nitrate (Al(NO3)3) is 213 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. Therefore, the percentage by mass of nitrogen in aluminum nitrate is (3 * 14) / 213 * 100 ≈ 19.7%.
# of AtomsAt Wt.Total Wt.Nitrogen214.006728.0134Hydrogen41.007944.03176Oxygen315.999447.9982Total Molecular weight80.04% of Nitrogen=28.01/80.04 = 35%
The formula for sodium nitrate is NaNO3, showing that each formula unit contains one sodium atom, one nitrogen atom, and three oxygen atoms. The gram atomic masses of sodium, nitrogen, and oxygen are 22.9898, 14.0067, and 15.9994 respectively. Therefore, the percentage by mass of nitrogen in the compound is: 100{14.0067/[14.0067 + 22.9898 + 3(15.9994)]} or about 16.4795, to the justified number of significant digits.
The relative molecular mass of Ca(NO3)2, also known as calcium nitrate, can be calculated by adding the atomic masses of calcium (Ca), nitrogen (N), and three oxygen (O) atoms. The atomic masses are 40.08 g/mol for calcium, 14.01 g/mol for nitrogen, and 16.00 g/mol for oxygen. When you add these values together, the relative molecular mass of Ca(NO3)2 is 164.08 g/mol.
off the top of my head = 102Let's break this down. Very easy- first, take the #atoms of each element, 1 calcium,2 nitrogen, 6 oxygen. You can pull these straight off of the chemical formula. Now, multiply by molar mass- on the periodic table. (calcium) 1*40.078=40.078, (Nitrogen) 2*14.0067=28.0134, (Oxygen) 6*16=96. Now, add 'em up. 40.078+28.0134+96=164.0914 (Grams/mole)nothing to it.
To find the mass of the nitrogen atoms in one mole of cadmium nitrate, calculate the molar mass of cadmium nitrate (Cd(NO3)2) and then multiply it by the number of nitrogen atoms in one mole of cadmium nitrate (2 nitrogen atoms). The molar mass of cadmium nitrate is 236.41 g/mol. Therefore, the mass of the nitrogen atoms in one mole of cadmium nitrate is 28.02 g.
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%
The molar mass of calcium nitrate is 164.1 g/mol. This is equivalent to 164,100 mg/mol.
The mass of silver nitrate is 30,6 g.
The maximum percentage of nitrogen by mass is about 78.08%, which is the composition of nitrogen gas (N2) in the atmosphere.
The mass percentage of nitrogen in ammonia (NH3) is 82.35%. This is calculated by dividing the mass of nitrogen in one mole of ammonia by the molar mass of ammonia, and then multiplying by 100 to get the percentage.