The Atomic Mass of sodium, Na is 23.0
Amount of sodium = mass of sample / atomic mass = 120/23.0 = 5.22mol
The mole of a metal, such as sodium, is generally assumed to consist of Avogadro's Number of single atoms. The gram atomic mass of sodium is 22.9898. The number of moles in 120 grams of Na is therefore 120/22.9898, or 5.22, rounded to the justified number of significant digits.
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
To find the molarity, first calculate the number of moles of calcium nitrite using its molar mass. Then, divide the number of moles by the volume of the solution in liters (240 mL = 0.24 L) to get the molarity.
In the process of photosynthesis, the overall reaction involves 6 molecules of CO2 producing 1 molecule of glucose. The molar mass of CO2 is 44 g/mol and the molar mass of glucose is 180 g/mol. To produce 180 grams of glucose, you would need 6 * 44 = 264 grams of CO2.
When 120g of glucose is converted to ATP in muscle cells, it produces 72g of water and 264g of carbon dioxide. This process involves the breakdown of glucose through cellular respiration, where glucose is oxidized to produce energy (ATP), water, and carbon dioxide.
120 grams of calcium contain 2,994 moles.
120 g calcium is equal to 3 moles.
i think its 120 (40x3)
The mole of a metal, such as sodium, is generally assumed to consist of Avogadro's Number of single atoms. The gram atomic mass of sodium is 22.9898. The number of moles in 120 grams of Na is therefore 120/22.9898, or 5.22, rounded to the justified number of significant digits.
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
n = 817 g x (1 mol / 120 g) = 6.81 mol
120
Sodium nitrate is soluble in water at any temperature. It has high solubility, and 120 grams of sodium nitrate will dissolve in 100 ml of water regardless of the temperature.
0.67 moles of C6H12O6
0,288 moles
120 ml of water weighs 120 grams
A set of Digital scales.