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10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
63 g of water are needed.
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed
Mole Ratio
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
Ca + 2 H2O ------> Ca(OH)2 + H2 so 2 moles of calcium react with 4 moles of water.
63 g of water are needed.
Na + 2H2O -----> H2 + NaOH If you have 2.5 moles water you need 1.25 mol elemental sodium
The chemical reaction isȘTiCl4 + 2 H2O = TiO2 + 2 HCl13 moles water are needed.
According to this balanced equation:Na2O + H2O --> 2NaOH42 moles Na2O react with 42 moles H2O
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed
Mole Ratio
The ratio H/O is 2.
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
1.2x10^25