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How many moles of H2O are produced when 0.721mol of octane is burned?
6,49 moles of water are obtained.
How many moles of water are in this reaction 2C8H18 25O2- 16CO2 18H2O?
There are 18 moles of water produced in the reaction. This is determined by the stoichiometry of the balanced chemical equation, which shows that for every 2 moles of C8H18 consumed, 18 moles of H2O are produced.
How many moles are in 95.0 gram of octane?
how many moles are in 95.0 gram of octane?
How many moles of water can be produced by burning 325g of octane in excess oxygen?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
How many moles of H2O are produced when 0.468 mol of octane is burned?
First write down the BALANCED reaction eq'n. Octane + oxygen = Water + Carbon Dioxide. 2CH3(CH2)6CH3 + 25O2 = 18H2O + 16CO2 The molar ratios are 2:25 :: 18:16 So '2' moles of octane produces 18 moles of water. So by equivlance 0.468 : x :: 2 : 18 Algebraically rearrgange x = (0.468/2) X 18 => x = 0.234 x 18 = > x = 4.212 moles water produces.
How many moles of H2O are produced when 0.721mol of octane is burned?
6,49 moles of water are obtained.
How many moles of water are in this reaction 2C8H18 25O2- 16CO2 18H2O?
There are 18 moles of water produced in the reaction. This is determined by the stoichiometry of the balanced chemical equation, which shows that for every 2 moles of C8H18 consumed, 18 moles of H2O are produced.
How many moles are in 95.0 gram of octane?
how many moles are in 95.0 gram of octane?
How many moles of water can be produced by burning 325g of octane in excess oxygen?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
How many moles of H2O are produced when 0.468 mol of octane is burned?
First write down the BALANCED reaction eq'n. Octane + oxygen = Water + Carbon Dioxide. 2CH3(CH2)6CH3 + 25O2 = 18H2O + 16CO2 The molar ratios are 2:25 :: 18:16 So '2' moles of octane produces 18 moles of water. So by equivlance 0.468 : x :: 2 : 18 Algebraically rearrgange x = (0.468/2) X 18 => x = 0.234 x 18 = > x = 4.212 moles water produces.
How many moles of are present in 16.0 of octane?
To determine how many moles of octane are present in 16.0 g, you would divide the mass of octane by its molar mass. The molar mass of octane (C8H18) is approximately 114.23 g/mol. Therefore, 16.0 g ÷ 114.23 g/mol = 0.14 moles of octane.
How many moles of water are produced from the combustion of 10.00 g of hydrogen?
10,55 moles of water are obtained.
How many moles of water vapor can be produced from 2 moles of ammonia?
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
How many moles of carbon and hydrogen are there in 5 moles of octane?
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
How many moles of H2SO4 are produced from 13 moles of H2O?
Sulfuric acid is not obtained from water.
How many moles of water H2O are produced from the reaction of 16 grams methane CH4 with an unlimited supply of oxygen O2. How many grams of H2O is this?
Two moles of water are produced.
How many moles of water will be produced if 6.00 grams of propane react?
To determine the moles of water produced from the reaction of 6.00 grams of propane, first calculate the moles of propane using its molar mass. Then, use the balanced chemical equation to find the moles of water produced based on the stoichiometry of the reaction.
