tall and short
60%
224
The phenotypic ratio of the offspring when a tall man marries a short woman is 3:1 (tall/short). The phenotypic ratio is figured by using the punnet square with the dominant allele for tall and the recessive allele for the short gene.
Because the offspring has both the Tall gene and the short gene
tall and short
no. in the second generation it will have a short offspring , but in the first generation it will have tall offspring
1000
3
If eastern cougars did not have offspring, they would become extinct. They have one or two at a time.
good stuff
An F1 x F1 cross would be a cross between heterozygous (Tt) parents. The offspring would be 1/4 TT, 1/2 Tt, and 1/4 tt. This would mean that 3/4 of the offspring would be tall, and 1/4 would be short.These offspring would be the F2 generation. Click on the related link to see an illustration of this using Punnett squares.
The combination of a female offspring would be XX
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None of the offspring would have colored spots..
It would depend on the dominant gene: I would compare the mother's parents eyelashes to the father's parents eyelashes, for each of the parent's eyelashes that are long it is an increase in 25% that the offspring will have long eyelashes. Unless half of the father's parents have long lashes then that shows the short lash gene is dominant.
Any cross of parents for a single trait where the dominant allele completely masks any expression of the recessive allele as follows:Parents are both heterozygous for the trait. For example Aa X Aa produces 75% of offspring with the dominant phenotype and 25% with the recessive phenotype.One parent is heterozygous for the trait and the other parent is homozygous recessive. For example: Aa X aa produces 50% offspring with the dominant phenotype and 50% offspring with the recessive phenotype.If the trait is co-dominant/non-dominant a heterozygote would have the median characteristic and a homozygote could be either of two phenotypes. If T is tall and t is short the Tt offspring would bemedium in this example. The way to produce offspring with only two phenotypes would be to cross a heterozygous parent with a homozygous parent. For Example:Tt X tt cross would produce 50% tt (short) offspring and 50% Tt (medium) offspring. A TT X Tt cross would produce 50% TT (tall) offspring and 50% Tt (medium) offspring.