60%
100%
1/4
The phenotypic ratio of the offspring when a tall man marries a short woman is 3:1 (tall/short). The phenotypic ratio is figured by using the punnet square with the dominant allele for tall and the recessive allele for the short gene.
Because the offspring has both the Tall gene and the short gene
tall and short
Homozygous for tall is TT Homozygous for short is tt All F1 offspring from this cross are Tt which makes them genotypically heterozygous and phenotypically tall.
tall.
good stuff
0% right answer 25%
no. in the second generation it will have a short offspring , but in the first generation it will have tall offspring
A. Offspring with heterozygous genotype 100 percent B. Offspring with homozygous dominant genotype 0 percent C. Offspring with at least one copy of recessive gene 50 percent
50 percent
More information is needed. The percent of offspring that will display the recessive trait from parents with Hh and HH will be different than the percent of offspring that will display the recessive trait from parents with hh and Hh.
12.5
50 percent
A cross between two homozygous parents will form a 100 percent chance of a heterozygous offspring. One homozygous parent must have the dominant allele, and the other must have the recessive allele. So, if the circumstances are correct, these characteristics will make for a 100 percent chance of a heterozygous offspring.
1 out of every 4 the percent will be 25%
13.3
25%