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How many mol of potassium are represented by 7.85e23 potassium atoms?
To find the number of moles of potassium, we need to first determine the molar quantity of potassium atoms in one mole. A mole is equivalent to Avogadro's number, which is 6.022e23 atoms per mole. So, 7.85e23 potassium atoms would be approximately 1.304 moles of potassium.
How many atoms are in 2 mole of potassium?
2 moles of ANY element contains 2x6.02x10^23 atoms of that element = 1.2x10^24 atoms.
How many atoms are in 3.50 moles of calcium?
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24
What would have the greatest mass 1 mole of iron atoms 2 moles of oxygen atoms 4 moles of carbon atoms or 1 mole of potassium atoms?
1 mole of iron atoms has the greatest mass - 55,845 g.
How many potassium atoms are in 0.5 moles of potassium?
In 1 mole of any substance, there are 6.02 x 1023 particles. This number is the avogadro constant. In 0.5mol of potassium, there would be 0.5 x 6.02 x 1023 = 3.01 x 1023 potassium atoms.
How many mol of potassium are represented by 7.85e23 potassium atoms?
To find the number of moles of potassium, we need to first determine the molar quantity of potassium atoms in one mole. A mole is equivalent to Avogadro's number, which is 6.022e23 atoms per mole. So, 7.85e23 potassium atoms would be approximately 1.304 moles of potassium.
How many atoms are in 2 mole of potassium?
2 moles of ANY element contains 2x6.02x10^23 atoms of that element = 1.2x10^24 atoms.
Which would contain more atoms a mole of K atoms or a mole of Au atoms?
Let's see. 1 mole K atoms = 6.022 X 1023 atoms * 19 electrons = 1.144 X 1025 electrons in one mole potassium ------------------------------------------------------------- 1 mole Au atoms = 6.022 X 1023 atoms * 79 electrons = 4.757 X 1025 electrons in one mole gold ------------------------------------------------------ A mole of gold, Au, atoms contains more electrons than a mole of potassium, K, atoms.
How many atoms are in 3.50 moles of calcium?
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24
What would have the greatest mass 1 mole of iron atoms 2 moles of oxygen atoms 4 moles of carbon atoms or 1 mole of potassium atoms?
1 mole of iron atoms has the greatest mass - 55,845 g.
How many atoms are in a sample of 1.83 moles of potassium (K) atoms?
Okay, a mole of potassium perchlorate contains 6.02x1023 formula units of potassium perchlorate, but you're asking about individual atoms. So, let's look at the formula: KClO3. That's 1 potassium, 1 chlorine, and 3 oxygens, for a total of 5 atoms per formula unit. Now, multiple 5 by Avogadro's number above, to get 30.1x1023, which simplifies to 3.01x1024 atoms.
Which would have a higher mass a mole of K atoms or a mole of Au atoms?
A mole of Au atoms would have a higher mass compared to a mole of K atoms because gold (Au) atoms have a larger atomic mass than potassium (K) atoms. The molar mass of a substance is determined by adding the atomic masses of the individual atoms in the mole.
What does one mole of potassium sulfate contain?
One mole of potassium sulfate, K2SO4, contains 2 moles of potassium (K) ions, 1 mole of sulfur (S) ion, and 4 moles of oxygen (O) atoms.
How many atoms in 19 g of potassium?
The molar mass of potassium is approximately 39.1 g/mol. Therefore, there are about 6.022 x 10^23 atoms in 39.1g of potassium, which is equivalent to one mole. In 19g of potassium, there would be about half that amount, or approximately 3.01 x 10^23 atoms.
How many potassium atoms are in 0.5 moles of potassium?
In 1 mole of any substance, there are 6.02 x 1023 particles. This number is the avogadro constant. In 0.5mol of potassium, there would be 0.5 x 6.02 x 1023 = 3.01 x 1023 potassium atoms.
How many atoms does 4KNO3?
One mole of KNO3 contains 4 potassium atoms, 4 nitrogen atoms, and 12 oxygen atoms, giving a total of 20 atoms.
How many moles of atoms are contained in 6.81 x 1024K atoms?
There are 1 mole of atoms in 6.022 x 10^23 atoms (Avogadro's number). Therefore, to find the number of moles in 6.81 x 10^24 atoms, you would divide the given number of atoms by Avogadro's number: 6.81 x 10^24 atoms / 6.022 x 10^23 atoms/mole = 11.33 moles.
