The molar mass of potassium is approximately 39.1 g/mol. Therefore, there are about 6.022 x 10^23 atoms in 39.1g of potassium, which is equivalent to one mole. In 19g of potassium, there would be about half that amount, or approximately 3.01 x 10^23 atoms.
To calculate the number of potassium atoms, you first need to convert the mass of potassium to moles using the molar mass of potassium (39.10 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of potassium atoms present in the given mass.
To find the grams of potassium in K2CrO7, first determine its molar mass. Potassium (K) has a molar mass of 39.10 g/mol, and K2CrO7 has two potassium atoms, so (39.10 g/mol) * 2 = 78.20 g/mol. Then, divide the mass of K2CrO7 by its molar mass to get the grams of potassium: (27.8 g) / (294.19 g/mol) ≈ 9.45 g of potassium.
The atomic mass of potassium is 39 ,therefore the number of mole is 39 /39,which is 1then multiple by Avogadro number you get 6.022*10^24
two elements and two atoms (potassium and chlorine)In one molecule of KCl, there are two elements (potassium and chlorine).The molecular weight of KCl is 74.55 g / mol.So, 74.55 g of KCl will contain 6.023 x 1023 molecules or 12.046 x 1023 atoms.
To calculate the number of potassium atoms present in 57.7 g of K2MnF6, first calculate the molar mass of K2MnF6. Then divide the given mass by the molar mass to get the number of moles of K2MnF6. Since there are 2 potassium atoms in each formula unit of K2MnF6, multiply the number of moles by Avogadro's number (6.022 x 10^23) and then multiply by 2 to find the number of potassium atoms.
To calculate the number of potassium atoms, you first need to convert the mass of potassium to moles using the molar mass of potassium (39.10 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of potassium atoms present in the given mass.
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
To find the grams of potassium in K2CrO7, first determine its molar mass. Potassium (K) has a molar mass of 39.10 g/mol, and K2CrO7 has two potassium atoms, so (39.10 g/mol) * 2 = 78.20 g/mol. Then, divide the mass of K2CrO7 by its molar mass to get the grams of potassium: (27.8 g) / (294.19 g/mol) ≈ 9.45 g of potassium.
The atomic mass of potassium is 39 ,therefore the number of mole is 39 /39,which is 1then multiple by Avogadro number you get 6.022*10^24
two elements and two atoms (potassium and chlorine)In one molecule of KCl, there are two elements (potassium and chlorine).The molecular weight of KCl is 74.55 g / mol.So, 74.55 g of KCl will contain 6.023 x 1023 molecules or 12.046 x 1023 atoms.
To calculate the number of potassium atoms present in 57.7 g of K2MnF6, first calculate the molar mass of K2MnF6. Then divide the given mass by the molar mass to get the number of moles of K2MnF6. Since there are 2 potassium atoms in each formula unit of K2MnF6, multiply the number of moles by Avogadro's number (6.022 x 10^23) and then multiply by 2 to find the number of potassium atoms.
To find the number of potassium atoms in a sample of K2Cr2O7, you first need to calculate the number of moles of K2Cr2O7 using its molar mass. Then, you can determine the number of moles of potassium atoms since there are 2 potassium atoms in each molecule of K2Cr2O7. Finally, use Avogadro's number (6.022 x 10^23) to convert the number of moles of potassium atoms to the actual number of atoms.
To calculate the number of atoms in 0.551 g of potassium (K), you first need to convert the mass to moles using the molar mass of potassium (39.10 g/mol). Next, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Therefore, 0.551 g of potassium would contain approximately 7.1 x 10^22 atoms.
To calculate the mass of 2x10^12 atoms of potassium, you first need to find the molar mass of potassium (39.10 g/mol). Then, divide the number of atoms by Avogadro's number to get the moles of potassium. Finally, multiply the moles by the molar mass to find the mass in grams, which in this case would be 0.01566 grams.
The atomic weight of K (Potassium) is 39.0983 g/mol
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
To find the number of potassium (K) atoms in 78.2 grams, first determine the molar mass of potassium, which is approximately 39.1 g/mol. Dividing 78.2 grams by the molar mass gives about 2.00 moles of potassium. Since one mole contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), multiplying 2.00 moles by (6.022 \times 10^{23}) results in approximately (1.20 \times 10^{24}) potassium atoms.