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The Atomic Mass of potassium is 39 ,therefore the number of mole is 39 /39,which is 1then multiple by Avogadro number you get 6.022*10^24
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How many potassium atoms are present in .01456 grams of potassium?
To calculate the number of potassium atoms, you first need to convert the mass of potassium to moles using the molar mass of potassium (39.10 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of potassium atoms present in the given mass.
How many atoms in 19 g of potassium?
The molar mass of potassium is approximately 39.1 g/mol. Therefore, there are about 6.022 x 10^23 atoms in 39.1g of potassium, which is equivalent to one mole. In 19g of potassium, there would be about half that amount, or approximately 3.01 x 10^23 atoms.
What is the molar mass of KOH?
molar mass is the mass of one mole of a substance. A mole is an amount, refers to Avogadros number which is 6.022 x 1023. a mole of atoms is that many atoms. therefore the molar mass of potassium hydroxide KOH is the mass of that many molecules of KOH. On the periodic table the mass number for each element is molar, so all you need to do is add together the molar mass of each element in the compound. Molar mass of potassium (K) is 39 Molar mass of oxygen (O) is 16 Molar mass of hydrogen (H) is 1 There is one of each of these elements in a molecule of potassium hydroxide therefore the molar mass = 39 + 16 + 1 = 56
How many grams of potassium are in 27.8 g of K2CrO7?
To find the grams of potassium in K2CrO7, first determine its molar mass. Potassium (K) has a molar mass of 39.10 g/mol, and K2CrO7 has two potassium atoms, so (39.10 g/mol) * 2 = 78.20 g/mol. Then, divide the mass of K2CrO7 by its molar mass to get the grams of potassium: (27.8 g) / (294.19 g/mol) ≈ 9.45 g of potassium.
How many atoms are in the compound KCI?
two elements and two atoms (potassium and chlorine)In one molecule of KCl, there are two elements (potassium and chlorine).The molecular weight of KCl is 74.55 g / mol.So, 74.55 g of KCl will contain 6.023 x 1023 molecules or 12.046 x 1023 atoms.
How many potassium atoms are present in .01456 grams of potassium?
To calculate the number of potassium atoms, you first need to convert the mass of potassium to moles using the molar mass of potassium (39.10 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of potassium atoms present in the given mass.
How many atoms in 19 g of potassium?
The molar mass of potassium is approximately 39.1 g/mol. Therefore, there are about 6.022 x 10^23 atoms in 39.1g of potassium, which is equivalent to one mole. In 19g of potassium, there would be about half that amount, or approximately 3.01 x 10^23 atoms.
What is the molar mass potassium?
The molar mass of the element potassium is 39 g/mol.
What is the molar mass of KOH?
molar mass is the mass of one mole of a substance. A mole is an amount, refers to Avogadros number which is 6.022 x 1023. a mole of atoms is that many atoms. therefore the molar mass of potassium hydroxide KOH is the mass of that many molecules of KOH. On the periodic table the mass number for each element is molar, so all you need to do is add together the molar mass of each element in the compound. Molar mass of potassium (K) is 39 Molar mass of oxygen (O) is 16 Molar mass of hydrogen (H) is 1 There is one of each of these elements in a molecule of potassium hydroxide therefore the molar mass = 39 + 16 + 1 = 56
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
How many moles of potassium are contained in 449 g of potassium?
To determine the number of moles of potassium in 449 g, you need to divide the mass (449 g) by the molar mass of potassium (39.1 g/mol). This calculation would give you the number of moles of potassium in 449 g.
How many grams of potassium are in 27.8 g of K2CrO7?
To find the grams of potassium in K2CrO7, first determine its molar mass. Potassium (K) has a molar mass of 39.10 g/mol, and K2CrO7 has two potassium atoms, so (39.10 g/mol) * 2 = 78.20 g/mol. Then, divide the mass of K2CrO7 by its molar mass to get the grams of potassium: (27.8 g) / (294.19 g/mol) ≈ 9.45 g of potassium.
How many atoms are in the compound KCI?
two elements and two atoms (potassium and chlorine)In one molecule of KCl, there are two elements (potassium and chlorine).The molecular weight of KCl is 74.55 g / mol.So, 74.55 g of KCl will contain 6.023 x 1023 molecules or 12.046 x 1023 atoms.
How many potassium atoms are present in 57.7 g of potassium hexafluoromanganate K2MnF6?
To calculate the number of potassium atoms present in 57.7 g of K2MnF6, first calculate the molar mass of K2MnF6. Then divide the given mass by the molar mass to get the number of moles of K2MnF6. Since there are 2 potassium atoms in each formula unit of K2MnF6, multiply the number of moles by Avogadro's number (6.022 x 10^23) and then multiply by 2 to find the number of potassium atoms.
How many potassium atoms are there in a sample of K2Cr2O7 having a mass of 24.43 g?
To find the number of potassium atoms in a sample of K2Cr2O7, you first need to calculate the number of moles of K2Cr2O7 using its molar mass. Then, you can determine the number of moles of potassium atoms since there are 2 potassium atoms in each molecule of K2Cr2O7. Finally, use Avogadro's number (6.022 x 10^23) to convert the number of moles of potassium atoms to the actual number of atoms.
Calculate the number of atoms in 0.551 g of potassium K?
To calculate the number of atoms in 0.551 g of potassium (K), you first need to convert the mass to moles using the molar mass of potassium (39.10 g/mol). Next, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Therefore, 0.551 g of potassium would contain approximately 7.1 x 10^22 atoms.
What is the molar mass of krypton?
There are 39.0983 grams in one mole of K (potassium). a mole is a number. you cannot ask how many moles are in potassium. but you may ask how many moles of a certain substance are in potassium.
