there is 2 in the first, 8 in the other and then there is ... ............ ....................... ............................... 9, yes 9, in the outer shell, the only atom to have 9 in the outer shell, except for Browningulain
An iodine atom contains electrons in the first five energy levels in its ground state. The electron configuration for iodine in its ground state is 1s22s22p63s23p63d104s24p64d105s25p5.
2 (two) 2 (two)
5 shells
five
5
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see what period it is in on the periodic table it is in period 6, so therefore there are 6 electron shells or energy levels
No, iodine has four electron shells, marked as "K", "L", "M", and "N". The number of electron shells is determined by the electron configuration of an element.
+/- 1 (5,7) are the listed oxidation states, but many of these elements that have many electron shells can reach deep into their valance shells for greater oxidation states due to a possibility of electron shielding.
Iodine (I) is the halogen with four occupied electron shells. It belongs to group 17 of the periodic table and has 53 electrons, filling up the first four electron shells.
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see what period it is in on the periodic table it is in period 6, so therefore there are 6 electron shells or energy levels
Both iodine and chlorine are halogens (group 17) and have 7 valence electrons.
No, iodine has four electron shells, marked as "K", "L", "M", and "N". The number of electron shells is determined by the electron configuration of an element.
+/- 1 (5,7) are the listed oxidation states, but many of these elements that have many electron shells can reach deep into their valance shells for greater oxidation states due to a possibility of electron shielding.
No, iodine has 5 electron shells. It has a total of 53 electrons and its electron configuration is [Kr] 5s2 4d10 5p5, indicating that it has 4 electron shells.
2, 8, 18, 18, 7.
Iodine (I) is the halogen with four occupied electron shells. It belongs to group 17 of the periodic table and has 53 electrons, filling up the first four electron shells.
That would be iodine (I).
The electronic configuration of iodine (I) is [Kr] 5s^2 4d^10 5p^5 in the K, L, and M shells. The electron configuration in the N shell is 5s^2 5p^5.
They have seven electrons in their outer shell they are in group seven on the periodic table.