Multiply by avagadro's number (6.022x1023) giving 3.203704x1023 atoms
4.65Mol
2.80x10^24 atoms x 1 mole/6.022x10^23 atoms = .465x10^1 mole = 4.65
0.100 moles silicon (SiO2 ) dioxide (2 mole O/1 mole Si)(6.022 X 1023/1 mole O) = 1.20 X 1023 atoms of oxygen ======================
How many silicon atoms are in a basic silicon-oxygen tetrahedron?i am thinking about 4..
6.45 moles X 6.02 X 10 to the 23 power will be right (use 3 significant figures in your answer)
2,80 1024 atoms of silicon equals 0,465 moles.
2,50 moles of silicon contain 15,055352142.10e23 atoms.
2.80x10^24 atoms x 1 mol/6.02x10^23 atoms = 4.65 moles
The answer is 0,465 moles.
4.65Mol
3.10 moles SiO2 (1 mole Si/1 mole SiO2)(6.022 X 1023/1 mole Si) = 1.87 X 1024 atoms of silicon =====================
1 mole of an element contains 6.022 X 1023 atomsso in 1.4324 moles no. of atoms is 8.659 X 1023 atoms
This is one of those (horrors!) Stoichiometry problems. 1. What is the Atomic Weight of Silicon 2. How many Moles of Silicon in 1 pound 3. Multiply Moles by Avogadros Number to get Number of Atoms. As always, math is left as an exercise for the student.
2.80x10^24 atoms x 1 mole/6.022x10^23 atoms = .465x10^1 mole = 4.65
0.100 moles silicon (SiO2 ) dioxide (2 mole O/1 mole Si)(6.022 X 1023/1 mole O) = 1.20 X 1023 atoms of oxygen ======================
A mole of the element silicon is generally considered to have Avogadro's Number of atoms, since there is no particular small number of silicon atoms that is known to have distinct and persisting chemical bonds different from those of any other part of a sample of silicon. The number shown in the question is about 10 times Avogadro's Number and therefore contains ten moles.
1,685,600,000,000,000,000,000,000 or 1.6856 septillion or 1.6856*10^24 atoms. ----------------------------------------------------------------------------- Each mole would have 6.023 x 1023 atoms in it So for 2.8 moles simply multiply the above by 2.8. You would get it easily