4.65Mol
Multiply by avagadro's number (6.022x1023) giving 3.203704x1023 atoms
There are 2 atoms of oxygen in each molecule of silicon dioxide (SiO2). Therefore, in 0.100 moles of SiO2, there would be 0.100 moles * 2 atoms = 0.200 moles of oxygen atoms. Finally, since 1 mole of any element contains 6.022 x 10^23 atoms, there are (0.200 moles) * (6.022 x 10^23 atoms/mole) = 1.204 x 10^23 atoms of oxygen in 0.100 moles of silicon dioxide.
To calculate the number of moles, you need to divide the number of atoms by Avogadro's number (6.022 x 10^23), which represents one mole. For 280 x 10^24 atoms of silicon, you would have 280 x 10^24 / 6.022 x 10^23 = approximately 46.5 moles of silicon.
6.45 moles X 6.02 X 10 to the 23 power will be right (use 3 significant figures in your answer)
To find the number of silicon atoms in 85.0 micrograms of silicon, you would first calculate the moles of silicon using its molar mass. Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
2,80 1024 atoms of silicon equals 0,465 moles.
The answer is 2,7 moles.
2,50 moles of silicon contain 15,055352142.10e23 atoms.
Multiply by avagadro's number (6.022x1023) giving 3.203704x1023 atoms
The answer is 0,465 moles.
To calculate the number of moles in 2.80x10^24 atoms of silicon, you first need to determine the molar mass of silicon, which is approximately 28.0855 g/mol. Next, you can use Avogadro's number, which is 6.022x10^23 atoms/mol, to convert atoms to moles. Divide the number of atoms by Avogadro's number to get the number of moles. Therefore, 2.80x10^24 atoms of silicon is equivalent to approximately 4.65 moles.
3.10 moles SiO2 (1 mole Si/1 mole SiO2)(6.022 X 1023/1 mole Si) = 1.87 X 1024 atoms of silicon =====================
To find the number of atoms in 15.6 g of silicon, you would first calculate the moles of silicon using its molar mass (28.09 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. The final calculation would yield the number of atoms in 15.6 g of silicon.
There are 2 atoms of oxygen in each molecule of silicon dioxide (SiO2). Therefore, in 0.100 moles of SiO2, there would be 0.100 moles * 2 atoms = 0.200 moles of oxygen atoms. Finally, since 1 mole of any element contains 6.022 x 10^23 atoms, there are (0.200 moles) * (6.022 x 10^23 atoms/mole) = 1.204 x 10^23 atoms of oxygen in 0.100 moles of silicon dioxide.
To determine the number of silicon atoms in 3.29 g, you first need to calculate the number of moles of silicon using its molar mass (28.0855 g/mol). Then, use Avogadro's number (6.022 x 10^23) to convert moles to atoms.
This is one of those (horrors!) Stoichiometry problems. 1. What is the Atomic Weight of Silicon 2. How many Moles of Silicon in 1 pound 3. Multiply Moles by Avogadros Number to get Number of Atoms. As always, math is left as an exercise for the student.
1,685,600,000,000,000,000,000,000 or 1.6856 septillion or 1.6856*10^24 atoms. ----------------------------------------------------------------------------- Each mole would have 6.023 x 1023 atoms in it So for 2.8 moles simply multiply the above by 2.8. You would get it easily