Want this question answered?
3
14 (+2 for network & host).
5 bits are necessary to create up to 30 subnets.
you need to reallocate 4 bits to creat 16 subnets. how do I get that? easy! 2 to the power of 4 gives us 16 subnets.
There are 16 bits available; it is up to you how many of those bits you reserve for the subnet, and how many for the individual hosts within each subnet.
1
There are 65,536 subnets available in an IPv6 /48 block.
A Class C IP address has 24 bits for network and 8 bits for host. So to have a subnet mask of 26 bits, you will need to use 2 bits from host part.Number of subnets is given by the formula : 2^(no. of bits used from host part).Hence number of subnets in this case would be = 2^2 = 4.For e.g. if the class C IP address is 200.168.210.0the 4 subnet addresses would be :11001000.10101000.11010010.00000000 = 200.168.210.011001000.10101000.11010010.01000000 = 200.168.210.6411001000.10101000.11010010.10000000 = 200.168.210.12811001000.10101000.11010010.11000000 = 200.168.210.192Note: The digits in bold are the mask bits.
At least one.
3
It depends on how many bits you are using for the network prefix. The formula is 2n - 2 for the number of subnets available in a prefix, or 2n if you allow the use of the 0th subnet.
126