4
1024
A 10-bit binary number can represent (2^{10}) different combinations. This is because each bit can be either 0 or 1, leading to (2) choices for each of the (10) bits. Therefore, (2^{10} = 1024) different combinations can be represented by 10 bits.
To find out how many different values can represented by a certain number of bits, we can use the following formula 2n-1 and that is because the first number is always a zero.Based on that 6 bits = 26- 1= 64-1=637 bits= 27-1= 1278 bits= 28-1=25510 bits= 210-1=1023# of bits1=12=33=74=155=316=637=1278=2559=51110=1023
10 bits
It takes 10 bits.
8.796 x 10^12 bits
10 Bytes OR 80 Bits Jaydeep Chakraborty
1000
10 bits would be required. 10 bits long (10 digits long) can represent up to 1024.
10 bits
240(10)=11110000(2)
10 mbps ethernet uses Manchester encoding where each symbol is represented by 2 bit sequence. Hence the bits/symbol is 2. Since data rate = bits/symbol x symbol/seconds, symbols/seconds = baud rate = 5 mega baudWhat_is_the_baud_rate_of_the_standard_10-Mbps_Ethernet