240(10)=11110000(2)
4.1 bit for 2,2 bits for 4,3 bits for 8,4 bits for 16.
This is because the byte values ​​are converted into bits. because you can only work with bits....
In order to know how many bits/second there are in 1 frame/second, you need to know how many bits are in that frame. In a typical asychronous serial protocol with 8 bits per frame, the bit rate would be 0.125 bits/second. If you are talking the IP network layer of TCP/IP, then the frame size is very dependent on the underlying message payload and headers.The original question, by the way, is invalid. Its asks "how many bits does...", but it should have asked "how manys bits per second does...".
for: faster, better readability against: memory isn't used optimally
23 can be represented in binary as 10111 and would therefore require 5 bits to represent.
Eight bits to the octet. The values are 0-255.
16 bits. Java char values (and Java String values) use Unicode.
16 bits per block
16 bits per block
65,536
There are 256 possible values (or characters) in 8 bits.
32 values. 2^5=32
2^12=4096
8192
1200
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...