The answer is 15,2.1021 atoms of uranium.
The answer is 0,1518.10e+23 atoms.
If these atoms are loose unities, not bonded in a molecule, it would be about 22 dm3 at 0oC and standard pressure (STP). If the atoms would have formed gas molecules, e.g. CO2 or SF6, the answer would be different, because 6.02 x 1023 molecules always take in a volume of about 22 dm3 at STP. But with CO2 you would have then 18 x 1023 atoms because there are 3 atoms in one molecule.
table 3.7 in prentice hall chemistry That's going to depend on the pressure of the sample as well as its temperature.
6g
That depends entirely upon what element or compound you are weighing....
The answer is 0,1518.10e+23 atoms.
Coal Uranium and natural gas. By Xzoctic 6G
1g = 100cg 6g x (100cg/1g) = 600cg
1g = 100cg 6g x (100cg/1g) = 600cg
600 cg
6g
6000 mg
600 cm
6g-g= subtract g to get 5g 6g-g=5g
(6g)(4qts/g)(2pts/qt)(2cups/pt)=(6g)16cups/g)=96 cups
6000mg. 1g is 1000mg
6g