during the formation of calcium iodide,calcium donates two of its +ve ions each to a fluorine atom(2 in number) thereby making its octet and also fulfills the octet formation of each of fluorine atom..
The calcium atom will transfer its two valence electrons, one to each of two iodine atoms, to form the compound calcium iodide, CaI2.
Ca + I2 --> CaI2 Each calcium gives up 2 electrons to iodine when forming calcium iodide.
It takes only one valence electron to form the calcium iodide compound.
it loses two electrons when forming a compuond.
One calcium atom will transfer one of each of its two valence electrons to one each of two iodine atoms. In the process, the calcium atom becomes a calcium ion with a 2+ charge, and each iodine atom becomes an iodide ion with a 1- charge. The opposite charges between the iodide and calcium ions form an electrostatic attraction called an ionic bond, forming the ionic compound calcium iodide. Ca + I2 ---> I- + Ca2+ + I- ---> CaI2
The formula for calcium iodide is CaI2. This means that the calcium atom has transferred one electron to each of two iodine atoms, for a total of two electrons transferred.
The calcium atom will transfer its two valence electrons, one to each of two iodine atoms, to form the compound calcium iodide, CaI2.
Ca + I2 --> CaI2 Each calcium gives up 2 electrons to iodine when forming calcium iodide.
It takes only one valence electron to form the calcium iodide compound.
Two electrons are transferred between calcium and oxygen to form calcium oxide.
2
ionic compound
it loses two electrons when forming a compuond.
Ca loses electrons. In general metals react in compound by losing some of their electrons, Ca is a metal.
The two outer shell electrons of a calcium atom are donated to an oxygen atom, forming calcium cations and oxygen anions that together constitute the salt compound calcium oxide.
One calcium atom will transfer one of each of its two valence electrons to one each of two iodine atoms. In the process, the calcium atom becomes a calcium ion with a 2+ charge, and each iodine atom becomes an iodide ion with a 1- charge. The opposite charges between the iodide and calcium ions form an electrostatic attraction called an ionic bond, forming the ionic compound calcium iodide. Ca + I2 ---> I- + Ca2+ + I- ---> CaI2
Well the charge on the compound would be stable (0) when bonded, because the Calcium has given it's electrons to the Oxygen atom. But the charge on the calcium ion itself would be 2+