It takes only one valence electron to form the calcium iodide compound.
Ca + I2 --> CaI2 Each calcium gives up 2 electrons to iodine when forming calcium iodide.
The calcium atom will transfer its two valence electrons, one to each of two iodine atoms, to form the compound calcium iodide, CaI2.
during the formation of calcium iodide,calcium donates two of its +ve ions each to a fluorine atom(2 in number) thereby making its octet and also fulfills the octet formation of each of fluorine atom..
A calcium atom will transfer its two valence electrons to two separate iodine atoms in the formation of calcium iodide. The calcium atom becomes a Ca2+ ion, and each iodine atom becomes a 1- iodide ion. The electrostatic force of attraction between the oppositely charged ions forms ionic bonds between the ions.Ca + I2 --> Ca + I + I --> Ca2+ + I- + I- --> CaI2Overall reaction:Ca + I2 ---> CaI2
One calcium atom will transfer one of each of its two valence electrons to one each of two iodine atoms. In the process, the calcium atom becomes a calcium ion with a 2+ charge, and each iodine atom becomes an iodide ion with a 1- charge. The opposite charges between the iodide and calcium ions form an electrostatic attraction called an ionic bond, forming the ionic compound calcium iodide. Ca + I2 ---> I- + Ca2+ + I- ---> CaI2
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The formula for calcium iodide is CaI2. This means that the calcium atom has transferred one electron to each of two iodine atoms, for a total of two electrons transferred.
Ca + I2 --> CaI2 Each calcium gives up 2 electrons to iodine when forming calcium iodide.
The calcium atom will transfer its two valence electrons, one to each of two iodine atoms, to form the compound calcium iodide, CaI2.
during the formation of calcium iodide,calcium donates two of its +ve ions each to a fluorine atom(2 in number) thereby making its octet and also fulfills the octet formation of each of fluorine atom..
A calcium atom will transfer its two valence electrons to two separate iodine atoms in the formation of calcium iodide. The calcium atom becomes a Ca2+ ion, and each iodine atom becomes a 1- iodide ion. The electrostatic force of attraction between the oppositely charged ions forms ionic bonds between the ions.Ca + I2 --> Ca + I + I --> Ca2+ + I- + I- --> CaI2Overall reaction:Ca + I2 ---> CaI2
One calcium atom will transfer one of each of its two valence electrons to one each of two iodine atoms. In the process, the calcium atom becomes a calcium ion with a 2+ charge, and each iodine atom becomes an iodide ion with a 1- charge. The opposite charges between the iodide and calcium ions form an electrostatic attraction called an ionic bond, forming the ionic compound calcium iodide. Ca + I2 ---> I- + Ca2+ + I- ---> CaI2
Iodine atom has 7 valence electrons, whereas Iodide ion has 8 valence electrons.
I believe you mean the formation of the compound calcium iodide. In the formation of calcium iodide, CaI2, the calcium atom transfers two valence electrons to two iodine atoms, with one electron going to each iodine atom. This causes the formation of a calcium ion, Ca2+, and two iodide ions, I-. The electrostatic attraction between the oppositely charged ions forms the ionic bonds that form the compound calcium iodide.
Two valence electrons are donated to two I atoms (or one I2 molecule) Ca --> Ca2+ + 2 e- 2 e- + I2 --> 2 I- In this way, taking both together CaI2, calcium iodide, is formed.
Calcium iodide.
Iodine is a non metal element. There are 53 electrons in a single atom. There are 7 valence electrons. The iodide ion I- has 54 electrons.