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How many electrons would be in the valence shells of iodine and chlorine?

Both iodine and chlorine are halogens (group 17) and have 7 valence electrons.


How many additional valence electrons does chlorine need to have a full valence shells?

11 electrons makes the third energy level complete. One


How many additional valence shells does chlorine need to have a full valence shell?

11 electrons makes the third energy level complete. One


In the formula CuCl2 what does the 2 stand for?

How many Chlorine (Cl) atoms there are. Since Cu has a valence shell of 2, it needs to bond with 2 Chlorine ions in order to create complete valence shells for the molecule.


How many valence electrons are in Cl atom?

There are 7 valence electrons in a chlorine atom. The atomic number of chlorine is 17, which means it has an electron configuration of 2,8,7. This shows it has 3 shells of electrons, with 7 in the outer level.


How many valence electron does chlorine?

The element chlorine has seven electrons in its valence shell.


If magnesium has two valence electrons while chlorine has seven how many chlorine atoms are needed to form an ionic bond with magnesium?

One chlorine atom will form an ionic bond with one magnesium atom. The magnesium will donate its two valence electrons to the chlorine atom, filling both of their valence electron shells.


How many valence electrons surround chlorine?

Chlorine has 7 valence electrons.


How many valence shells in radium?

Radium has seven electron shells; the valence of radium is 2+.


How many valence electrons in chlorine-37?

In every chlorine atom, there are seven valence electrons.


Number of valence electrons in chlorine?

I think that because chlorine has 17 electrons in all, and ten of them are filled up on the first two shells, then seven of them should be on the third shell, so seven of them are valance electrons.


What is the valence shell for chlorine?

There are 7 electrons on the valence shell. Chlorine requires one electron to make it complete and the ion would therefore be Cl- (one minus charge)