Both iodine and chlorine are halogens (group 17) and have 7 valence electrons.
I think that because chlorine has 17 electrons in all, and ten of them are filled up on the first two shells, then seven of them should be on the third shell, so seven of them are valance electrons.
11 electrons makes the third energy level complete. One
There are 7 valence electrons in a chlorine atom. The atomic number of chlorine is 17, which means it has an electron configuration of 2,8,7. This shows it has 3 shells of electrons, with 7 in the outer level.
An iodine atom has 46 core electrons. Core electrons are the inner electrons that are not involved in chemical bonding. In the case of iodine, the core electrons would include the 36 electrons found in the first four electron shells.
There are 7 electrons on the valence shell. Chlorine requires one electron to make it complete and the ion would therefore be Cl- (one minus charge)
11 electrons makes the third energy level complete. One
One chlorine atom will form an ionic bond with one magnesium atom. The magnesium will donate its two valence electrons to the chlorine atom, filling both of their valence electron shells.
46
Hydrogen and helium follow the duet rule, which means they strive to have a full valence shell with two electrons. Hydrogen can achieve this by gaining one electron, while helium already has a full valence shell with two electrons.
Yes they have eight electrons in their valence shells. This is why they are not reactive. All elements have valence shells.
3
Chlorine- Group VII- It has 7 valence electrons Group VII A- It does not lose electrons from its penultimate shell. Period 3- It has 17 electrons, therefore, electronic configuration is 2,8,7...3 shells