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Depends on the subnet. For the subnet of 192.168.1.0, the first usable IP address is 192.168.1.1. This is typical of a default wireless router setup. Valid usable IP addresses under this scenario is 192.168.1.1 to 192.168.1.254.
You can use up to 254 devices in this case.
65,534
253. Valid addresses would be from 10.20.50.1 to 10.20.50.254 10.20.50.0 is the network address. 10.20.50.255 is the network broadcast address. Any network with a subnet mask of 255.255.255.0 will support 253 hosts.
This is a network address
To Know any subnet of this IP you must provide the Subnet mask, otherwise it is impossible to know what is the subnet.
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Check out this website it has the IP and Subnet mask broken down by subnets and addtional host. http://www.oceanwave.com/technical-resources/network-admin/ip.html 2046 http://www.oceanwave.com/technical-resources/network-admin/ip.html
4.1 to 7.254
This is not a valid IP address - a valid IP address has 4 bytes. Also, you can't guess the subnet mask from looking only at the IP address; there are usually several options.
lmfao you really thought you where going to get the answer
The maximum number of host bits that can be borrowed from a class A address is 22 (technically you could borrow 23 but the resulting network would be useless). A class A address uses 8 bits for its network address and 24 bits for its host addresses. Class A uses a subnet mask of 255.0.0.0 You can only borrow 22 bits (instead of 24) because a valid network requires 4 addresses: A network address, two host addresses and a broadcast address. These networks would result in 30 bits used for the network address and 2 bits used for the host addresses. These networks use a subnet mask of 255.255.255.252