Molarity, not moles. Simple equality will do here.
(0.200 M NaOH)(X milliliters) = (0.100 M H3PO4)(5.00 milliliters)
0.200X = 0.5
X = 2.5 milliliters sodium hydroxide solution needed
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KOH for potassium hydroxide, and H3PO4 for phosphoric acid.
Hydroxide compounds such as sodium hydroxide (NaOH) are bases. Bases do not neutralize other bases. Acids neutralize bases.
Yes. Vinegar will neutralize potassium hydroxide to form a mildly alkaline solution of potassium acetate.
98g of phosphoric acid require 120g of sodium hydroxide to produce sodium phosphate so 150g phosphoric acid will require = 120/98x150= 183.67g sodium hydroxide.
Ca3(PO4)2 + H2O
No, because one mole of calcium hydroxide constitutes two equivalents of calcium hydroxide for neutralization, but one mole of phosphoric acid constitutes three equivalents of phosphoric acid for neutralization. Therefore, one mole of calcium hydroxide will neutralize only 2/3 of one mole of phosphoric acid.
KOH for potassium hydroxide, and H3PO4 for phosphoric acid.
0.0532
Hydroxide compounds such as sodium hydroxide (NaOH) are bases. Bases do not neutralize other bases. Acids neutralize bases.
0.0932 L
Phosphoric Acid dissociates to give off 3H+ ions, meaning that one mole of Phosphoric acid reacts with three mols of sodium hydroxide. Using the equation n = c x v n = 0.1 x 0.05 =0.005 mols of OH ions in the solution therefore there are 0.005/3 = 0.00167 So the volume of phosphoric acid - v = n/c v = 0.00167/0.2 v = 0.00835 l = 8.4ml of Phosphoric Acid reacts completely with Sodium hydroxide
Yes. Vinegar will neutralize potassium hydroxide to form a mildly alkaline solution of potassium acetate.
98g of phosphoric acid require 120g of sodium hydroxide to produce sodium phosphate so 150g phosphoric acid will require = 120/98x150= 183.67g sodium hydroxide.
The chemical equation is written out as:3KOH + H3PO4 -> 3H2O + K3PO4.So, if you do your mole bridge, you take your moles of Phosphoric acid (1.56) and do some quick stoichiometry.1.56 mole H3PO4 x (3 mole KOH)/(1 mol H3PO4). This comes out to.... 4.68 moles of KOH is required to neutralize 1.56 moles of H3PO4.
iron(II) hydroxide + phosphoric acid 3Fe(OH)2 + 2H3PO4 => Fe3(PO4)2 + 6H2O
Yes
Hydrochloric acid Sulfuric acid Phosphoric acid Sodium hydroxide Calcium hydroxide Potassium hydroxide