To get 0.15 moles of NaCl,
mass of NaCl = moles * molar mass
= 0.15 * (23+35.5)
= 8.775 g
and 0.15M is 0.15 mole of NaCl in on liter solvent which equals 8.775 g then ypu add solvent up to 1 liter.
0,15 M NaCl equal a concentration of 8,776 g/L.
The answer is 4,383 g.
117 grams of NaCl
0.95% * 500 g = 4.75 g NaCl
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
25ml of the 4M stock solution used
You need 58,44 mg of ultrapure NaCl; dissolve in demineralized water, at 20 0C, in a thermostat, using a class A volumetric flask of 1 L.
2.5 g of Nacl is to be dissolve in 100ml of water gives 10ppm of Na solution.
2.5gm require 100ml of solution 100ml solution require 2.5gm 50ml require 50x2.5/100=1.25ml
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
For 100 mM NaCl solution in 1L: Formula weight: 58.44 g/L Answer: 5.844 g/L if you want in 500 mL---2.922 g if you want in 250 mL---1.461 g if you want in 100 mL---584.4 mg
In order to determine this, it is necessary to know what solution we are looking at. One we know that we can look at the grams in a mole of the substance and determine the percentages based on molecular weight.
0.9% means there is 0.9 grams NaCl per 100ml of solution. So 1000 ml of 0.9% sodium chloride contains 9.0 grams of NaCl.
It depends on how much solution you have!"1 molar solution" means that 1 litre of the solution contains 1 mole of solute (in this case, Na+ and Cl- ions). Therefore, 1 litre of 1M NaCl will contain 1 mole of sodium chloride. 1 mole is avagadro's number (6.02x1023) of a substance. If you have two litres of solution, obviously, you will have twice this number, for example.Note, though, that there are NO molecules of sodium chloride - sodium chloride is not a molecular substance.