The circuit voltage or the resistance of the individual bulb is needed to answer this question.
Divide the total power (400 W) by the supply voltage.
it depends on how the bulbs are connected....if it is connected in series,supply (ex 220/4)...in paralell conn the bulb voltage is same as supply(al 4 bulbs)
Assuming the bulbs are identical, the voltage drop across each one is inversely proportional to the number of bulbs. So, for example, 240V could power 20 12V bulbs in series. In addition, the circuit would have to be able to supply the necessary current.
The bulb is dim.Because,the voltage is drops in series connection so you add more bulbs in series the last bulb got low voltage that reason for the bulb is dim
If it is in the same circuit, the voltage would not be the same. ANSWER: That is possible if both bulbs have the same rating of volts and amperes
For any lamp to operate at its rated power, it must be subject to its rated voltage. If you connect, say, three identical 120-V rated lamps across a 120-V supply, then each lamp will be subject to one-third of its rated voltage. As a result each lamp will not be able to achieve its rated power. If the lamps have different power ratings, then it is rather more complicated, with the most powerful lamp becoming the dimmest while the least powerful lamp becoming the brightest.
If all the bulbs are connected in parallel, and there is enough current, yes, the brightness will be the same. The voltage (which is the amount of energy in every charge), remains the same for all bulbs
Nothing.
Voltage remains constant; current increases.
if the resistance of bulb A is 2x that of B then there will be twice as much voltage across it (ratio 2:1 ). both voltages shall equal the system voltage assuming they are in series and there are no other components in the circuit if the bulbs are in parallel the voltage across them will be equal and that of the system
All of the bulbs will become dimmer as more bulbs are added.
The voltage of the bulbs is needed to answer this question. If we assume the voltage is 120 then the maximum wattage allowed on a 15 amp circuit is 1800 watts before the circuits over current device will trip. 1800/60 = 30 bulbs. To be certain that the circuit does not trip, only connect 29 bulbs to the circuit. If the circuit is considered as a continuous load then the load rating has to be reduced to 80% capacity. 1800 x .8 = 1440. With this de rating the number of bulbs allowed on the circuit would be reduced to 24 bulbs. This circuit would have to be a dedicated circuit and could not be combined with receptacles which could vary the load depending on what is plugged into them.
Two bulbs in parallel are brighter than the same two bulbs in series, given the same potential voltage, because there is twice the available voltage to each bulb.
They don't unless you speaking about a parallel circuit in which total currect would be the sum of all the currents in each light bulb (The more light bulbs, the more current draw) If you're talking about a series circuit, nothing at all happens to the current, as in a seires circuit current is constant throughout the entire circuit (voltage changes). In a case such as this the more light bulbs in the circuit, the less the voltage becomes across those bulbs (furthest from the source), thus they will become dimmer due to lower power (P=IE).
the bulbs would be very bright seeing as the two or more light bulbs have very easy excusable paths for electricity to flow and get to the light bulbAnswerBecause the voltage across each branch of a parallel circuit is the same, each lamp will be subject to its rated voltage and, therefore, will operate at its rated power output.
Yes. The current is inversely proportional to the resistance. I = V / R where I is current, V is voltage, and R is resistance. Adding light bulbs adds resistance. Current is constant throughout a series circuit; it doesn't change no matter what. Voltage changes.
Assuming the bulbs are identical, the voltage drop across each one is inversely proportional to the number of bulbs. So, for example, 240V could power 20 12V bulbs in series. In addition, the circuit would have to be able to supply the necessary current.
The bulb is dim.Because,the voltage is drops in series connection so you add more bulbs in series the last bulb got low voltage that reason for the bulb is dim
The voltage across a battery in a parallel circuit is equal to the voltage across each bulb because Kirchoff's Voltage Law (KVL) states that the signed sum of the voltages going around a series circuit adds up to zero. Each section of the parallel circuit, i.e. the battery and one bulb, constitutes a series circuit. By KVL, the voltage across the battery must be equal and opposite to the voltage across the bulb. Another way of thinking about this is to consider that the conductors joining the battery and bulbs effectively have zero ohms resistance. By Ohm's law, this means the voltage across the conductor is zero, which means the voltage across the bulb must be equal to the voltage across the battery and, of course, the same applies for all of the bulbs.