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When two 4-ohm resistors are connected in parallel across 12 volts:

-- Each resistor has 12V across it, so the current is I = E/R = 12/4 = 3 amperes.

-- The total current from the battery is 6 amperes.

-- The effective resistance as seen by the battery is R = E/I = 12/6 = 2 ohms.

-- If you didn't know the voltage of the battery, you would calculate the

effective resistance of the parallel resistors in advance like this:

1/R = 1/4 + 1/4 = 1/2

R = 2 ohms.

When you connected them to a battery, the battery would agree.

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12y ago
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12y ago

Use ohm's law: amperage I = voltage V divided by resistance R.

I in amps = 12 volts / 4 ohms = 3 amps.

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12y ago

Using Ohms Law:

12 volts ÷ 4 ohms ÷ 3 amps

So 3 amps is flowing through said circuit.

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14y ago

V = I * R
V = 12 V
R = 4 ohms
Solve for R.
R = 3 amps.

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13y ago

V = Current x Resistance

Rtot = 1 / (1/4 + 1/6) = 1/(3/12 + 2/12) = 12/5 = 2.4

I = 12/2.4 = 5 Amps

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13y ago

Ohm's Law

Voltage = Current x Resistance

V = I x R

I = 12/10 Amps

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13y ago

Ohm's Law: Current = voltage divided by resistance

12 volts divided by 4 ohms = 3 amperes.

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13y ago

12 (volts) / 3000 (ohms) = .3 (miliamps)

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9y ago

In amps it is twelve divided by four.

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11y ago

3 Ampere

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Q: How much current flows through a circuit if the if the resistance is 4 ohms and there is a 12-volt battery?
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