It depends on what kind of amp it is. Is it an audio amp or an rf amp . .
A 3 kW audio amp would draw about 300 watts on average at most, so with a good reservoir capacitor the supply current would be 0.2 amps. A 3 kW rf amp for AM radio would draw about 4500 watts so the supply current would be 3 amps.
The battery charger can be used but it is not recommended. The battery charger does not have filtering on the its output like a power supply does. You will probably hear an AC ripple on the amplifier which will become very annoying when listening to the amplifier.
Power equals voltage times current in amps. The value of amps used is needed to do the math.
Power (watts) = current (amperes) * voltage (volts) Current (amperes) = voltage (volts)/resistance (ohms) 120 watts = current * 120 volts current = 1 ampere 1 ampere = 120 volts/resistance resistance = 120 ohms
Basically, Power = Current*Voltage Current = Power/Voltage Current = 15/120 Current = 0.125A or 125mA
Impossible to answer 2 amps could carry a lot of power if the voltage is high, and 7.2 volts could carry a lot of power if the current is high.
Volts cause current to flow through the load. The current is measured in amps, and the volts multiplied by the amps gives the power in watts.
The power supply in either a guitar amplifier or in a professional sound amp reduces the 110v alternating current to a direct current. Also it reduces the voltage that can be used by the speakers, usually 12+ volts. Also if there where no power supply and there could be a possible way of reducing the voltage that could be used in the same was a direct current, you would here a constant phasing type noise from the current alternating. A power supply unit converts power that can be used in correctly in sound frequencies.
Power = voltage times current, and the power loss is the loss in the line, I^2 * R. At 11,000 volts, the current will be (11,000 / 415 = ) 3.77% of what it is at 415 volts. So the power loss in the line at 11,000 volts will be (3.77% ^2 = ) .14% of what it is at 415 volts.
Divide Watts by Volts ; this gives you Amps.
No. An amplifier designed for an 8 ohm load works best with an 8 ohm load. You can connect a 4 ohm load to it, but the current rating curve of the amplifier will not match the voltage rating curve, and will will not achieve rated power. Attempting to achieve rated power will result in damage to the amplifier. Look at this mathematically... If the amplifier is rated 100 watts into 8 ohms, then it can produce 28 volts doing so. It will also produce 3.5 amperes at that power. So, when we say the amplifier is rated 100 watts into 8 ohms, we mean that the amplifier is rated 28 volts or 3.5 amperes, whichever comes first. Connect a 4 ohm load to this amplifier, and 3.5 amperes will induce 14 volts and 50 watts. You cannot get 100 watts because that would require 5 amperes and 20 volts, and the amplifier cannot produce 5 amperes.
The battery charger can be used but it is not recommended. The battery charger does not have filtering on the its output like a power supply does. You will probably hear an AC ripple on the amplifier which will become very annoying when listening to the amplifier.
Power = Voltage x Current Watts = volts x Amps
Basically if you know the Voltage supply and the power used by an appliance then you use the formula for power which is Power = Volts x Amps. Rearrange so Amps (current) = Power / Volts If power was 2400 Watts and Volts was 240 the Current would be 2400 / 240 = 10 Amps
3 things Volts, ohms, and amps
The Alpine v12 MRV-F505 amplifier puts out up to 200 watts of RMS power at 4 Ohms and using 12 volts. At 14 volts, it puts out up to 400 watts of RMS power with a bridged 4 Ohms ratio.
Power, in 'watts'.
You are confusing electrical potential (Volts) and power (Watts). The equation for power (watts) is P = VI where V is volts (a measure of electrical "pressure") and I is current in amperes (the rate of flow of electricity). If the system is 120V and the power used is 600W then the current used is 5A. If the system is 240V and the power used is 600W then the current used is 2.5A.