Use stoichometry to figure this out. 1 mole Fe * 56 g Fe ...............1 mole Fe
1.0088525g 0.0010088525kg
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
1 mole of EDTA will chelate with 1 mole of Ca2+ ions or 1 mole of Fe2+ or Fe3+ ions.
nitrogen weighs 14, hydrogen weighs 1, so NH3 weighs 14+(3x1)=17grams
Use stoichometry to figure this out. 1 mole Fe * 56 g Fe ...............1 mole Fe
1.0088525g 0.0010088525kg
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
It is 55.8 grams.
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
1 mole of O (oxygen) weighs 15. 9996 grams. By definition, 1 mole of any element is equal to its atomic weight expressed in grams. 1 mole is equal to 6.02 x 1023 atoms of that element.
40 g of Ca = 1 mole So 808 g of Ca = 20.2 mole
The species is; Ca(NO3)2 ( NO3(-) is a polyatomic ion and is in parenthesis ) 7.5 grams Ca(NO3)2 (1 mole Ca(NO3)2/164.1 grams)(2 mole N/1 mole Ca(NO3)2)(6.022 X 10^23/1 mole N) = 5.5 X 10^22 atoms of nitrogen
First of all, we should know what a mole and molar mass of an element means. Then answering this question would be easy. Mole is a number( like pi, 1, 2, etc.). It is approximately 6.0225 *1023 . 1 mole of anything is same as the number of atoms in 12 grams of Carbon C12 sample. The mass of mole of an element/compound is called it's molar mass expressed in grams. The molar mass of a monoatomic element is equal to it's mass number. So, we know Ca's mass number = 40. that means 1 mole of Ca weighs 40 grams. =>1/40 mole of Ca weighs 1 gram. =>(1/40)*23 moles of Ca weighs 23.0 gram. =>0.575 moles of Ca weighs 23.0 gram. So there are 0.575 moles of Ca atoms in 23.0g of Ca
1 mole of EDTA will chelate with 1 mole of Ca2+ ions or 1 mole of Fe2+ or Fe3+ ions.
To make 1 mole carbon dioxide it takes 2 moles of HCl and one mole of Ca-carbonate.
The atomic mass of calcium, Ca is 40.1. First we calculate the amount in moles of calcium in a 98.5g pure sample.Amount of Ca = 98.5/40.1 = 2.46mol So there are 2.46 moles of Ca (or Ca atoms).