One mole of atoms of an element is equal to the Atomic Mass of that element expressed in grams.
Nitrogen-14
so one mole of nitrogen weighs 14 g
Since the normal formula for elemental nitrogen is N2, this answer is twice the atomic mass of nitrogen or 28 grams. The mass of a mole of nitrogen atoms is half this.
C. 28
It is 46 grams.
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
At 0C and 101,325 kPa: the mass of 186 mL nitrogen is 0,232 686 g.
15 grams of nitrogen are equal to 1,071 moles.
gram atomic mass (or atomic mass) of nitrogen (N) is 14 u.
It is 46 grams.
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
31.4
One molecule of nitrogen has a mass of approximately 4.65173 x 10-23 grams.
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
At 0C and 101,325 kPa: the mass of 186 mL nitrogen is 0,232 686 g.
First you need to find the atomic masses of each element involved in the compound NH3, and add them up to find the total molecular mass of ammonia.Nitrogen = 14.0 gramsHydrogen = 1.01 × 3 atoms = 3.03 grams----------------------------------------------------Ammonia = 17.03 gramsThen you take the mass of nitrogen in one molecule and divide it by the total mass to find the percent composition.14.0 grams Nitrogen ÷ 17.03 grams Ammonia = .822 = 82.2% nitrogen in ammoniaThen you simply need to take 82.2% of 7.5 grams to find how much nitrogen is in that particular amount.82.2% × 7.50 = 6.17 grams of nitrogen in 7.50 grams of ammonia
46 grams XP!
Yes the number of moles = the number of grams in a given sample / the molecular mass of the substance. Ex. to convert 50 grams of nitrogen to # of moles of nitrogen, you divide 50g by 14.01g (the molecular mass) and you have 3.57 mol Nitrogen
A sample of a compound contain 1.52 g of Nitrogen and 3.47 g of Oxygen. The molar mass of this compound is between 90 grams and 95 grams. The molecular formula and the accurate molar mass would be N14O35.
You would first calculate the atomic mass of chlorophyll, which would be 892.9 g/mol (I did not calculate this out, but looked it up b/c of the complexity of the calculation). Then find the molar mass of the Nitrogen part of the chlorophyll (4 mol *14.01 g/mol=56.04 grams). Then, take 56.04 grams/892.9grams= .06276, or 6.276% nitrogen by mass