You would first calculate the Atomic Mass of chlorophyll, which would be 892.9 g/mol (I did not calculate this out, but looked it up b/c of the complexity of the calculation). Then find the molar mass of the Nitrogen part of the chlorophyll (4 mol *14.01 g/mol=56.04 grams). Then, take 56.04 grams/892.9grams= .06276, or 6.276% nitrogen by mass
The molecular formula of ammonium carbonate is (NH4)2CO3. The molar mass of nitrogen in ammonium carbonate is 28.02 g/mol. The molar mass of ammonium carbonate is 96.09 g/mol. To calculate the mass percent of nitrogen in ammonium carbonate, you would divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100. This gives a mass percent of nitrogen in ammonium carbonate of around 29.1%.
The gas with a percent volume of 78.09 is nitrogen (N2).
78%
There is a formula to calculate the mass percent composition (which can be found in your reference table T for chemistry students)mass of element----------------------- X 100gram-formula massFirst of all you need to find the gram formula mass:2 N atoms= 2(14.0 amu) = 28.0 amu6 O atoms= 6(16.0 amu)= 96.0 amuthen add together124 amuThen plug in with the formula:(2X 14)----------- X 100% = 22.58% = % Nitrogen124 amuTo check to make sure the answer is correct the percentages of the individual elements must addd up to 100%. So you would then need to find the % oxygen. which is 77.41%. So in this case 77.41%+ 22.58%is 99.99% which can be rounded to 100% so in this case the answer is correct.
Nitrogen and oxygen make up more than 95 percent of an inhaled breath. Nitrogen accounts for about 78 percent, while oxygen makes up around 21 percent.
To calculate the percent nitrogen in common fertilizers, you can use the formula: Nitrogen (Amount of Nitrogen in fertilizer / Total weight of fertilizer) x 100. This formula helps determine the nitrogen content in the fertilizer, which is important for plant growth and health.
To calculate the percent composition of nitrogen in NH4 2HPO4, first calculate the molar mass of NH4 2HPO4 ( nitrogen: 14.01 g/mol, hydrogen: 1.01 g/mol, phosphorus: 30.97 g/mol, oxygen: 16.00 g/mol). Then, find the molar mass of nitrogen in NH4 2HPO4 ( nitrogen: 14.01 g/mol x 2). Finally, divide the molar mass of nitrogen by the molar mass of NH4 2HPO4 and multiply by 100 to get the percent composition of nitrogen.
To find the number of units of 32 percent nitrogen (N) in one gallon, you need to calculate the total weight of nitrogen in that gallon. One gallon of water weighs approximately 8.34 pounds. Thus, 32 percent of 8.34 pounds is about 2.67 pounds of nitrogen. Therefore, there are 2.67 pounds of nitrogen in one gallon of a 32 percent N solution.
To find the mass percent of nitrogen in NF3, you need to calculate the molar mass of NF3 and then determine the mass of nitrogen in one mole of NF3. The molar mass of NF3 is 71.001 g/mol. The molar mass of nitrogen in NF3 is 14.007 g/mol. Therefore, the mass percent of nitrogen in NF3 is (14.007 g/mol / 71.001 g/mol) * 100% ≈ 19.76%.
The percent of nitrogen in sodium nitrate is 16,47 %.
The molecular formula of ammonium carbonate is (NH4)2CO3. The molar mass of nitrogen in ammonium carbonate is 28.02 g/mol. The molar mass of ammonium carbonate is 96.09 g/mol. To calculate the mass percent of nitrogen in ammonium carbonate, you would divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100. This gives a mass percent of nitrogen in ammonium carbonate of around 29.1%.
69%
A forty pound (40) bag is the amount of 25 percent nitrogen fertilizer needed for a 970 square foot bed.Specifically, calculate the amount of 25 percent nitrogen needed for a 1,000 square foot bed. Convert the 25 percent by multiplying it by 100 to get 4. Then divide 4 by 1,000 square feet to get 38.8 pounds.
To calculate the mass percent of nitrogen in ammonium carbonate ((NH4)2CO3), first find the molar mass of the compound: (2 x 14) + 12 + 3 x 16 = 96 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. The mass percent of nitrogen in (NH4)2CO3 is (2 x 14) / 96 x 100 = 29.2%.
The molar mass of CN2H4O is 42 g/mol. The molar mass of nitrogen is 14 g/mol. To find the percent of nitrogen in CN2H4O, divide the molar mass of nitrogen by the molar mass of CN2H4O and multiply by 100. The percent of nitrogen in CN2H4O is approximately 33.3%.
The gas with a percent volume of 78.09 is nitrogen (N2).
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