Assuming a perfect machine (doesn't have any internal resistance), an EMF of 45*35 = 1575 volts is required. Actual EMF required by the machine will include the voltage drop internal to the machine, so 1575V constitutes a minimum necessary value.
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
Power in a circuit is inversely proportional to the resistance, all other things being equal. Voltage equals amperes time resistances, so amperes equals voltage divided by resistance. Watts equals voltage times amperes, so watts equals voltage squared divided by resistance.
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Using Ohm's law V:IR .I:V/R..I:100/5-20...I-20ampere
No, it is the current (amperes) that vary according to the resistance.
The three electrical quantities are current voltage and resistance. Current is measured in amperes (A) and is the rate at which electricity flows through a conductor. Voltage is measured in volts (V) and is the electrical force pushing the current through the conductor. Resistance is measured in ohms () and is the opposition to the flow of current. Current - measured in amperes (A) Voltage - measured in volts (V) Resistance - measured in ohms ()
"Ohm" and its multiples is not a unit of current."Ampere" and its multiples is.The current through a 2.2-megohm resistance is(the voltage across the resistance)/(2,200,000) amperes .
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
10 volts applied to 5 ohms would cause a current flow of 2 amperes. Current = voltage divided by resistance.
U = RxI so 11x20=220 volts
Power in a circuit is inversely proportional to the resistance, all other things being equal. Voltage equals amperes time resistances, so amperes equals voltage divided by resistance. Watts equals voltage times amperes, so watts equals voltage squared divided by resistance.
If the resistance of the wire is 30 ohms and the voltage between the two ends of the wire is 45 volts,then the current through the wire isI = E/R = (45/30) = 1.5 amperes.
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The number of watts produced by a current of 1.25 amperes can only be known if you also know either the applied voltage which caused that current to flow (W=I x E); or if you know the resistance through which the current flows. (W= I2 R).
Resistance is the measure of the degree to which an object will oppose an electric current. The SI unit for resistance is Ohm (Ω). Resistance can be found using the formula R=V/I where R=resistance (Ohms) V=the potential difference across the object (Volts) I=the current through the object (Amperes)