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The equation Q=mcΔ t calculates the amount of energy for a body of mass to raise a unit temperature per unit mass. The specific heat capacity of water is 4.19 J/g°C which means that it takes 4.19 J to raise 1 g of water to 1°. The specific heat capacity also depends on what the surrounding temperature is. 4.19 J/g°C is the specific heat capacity at room temperature. Since temperature is the measurement of the average kinetic energy of the particles, the motion of particles in water affects the specific heat capacity which ultimately affects how much energy is needed to heat up water.
Specific heat capacity (equation Q=mc��T) is the measure of the energy required in Joules to raise 1kg of a substance by 1.0 K (numerically equivalent to 1 C)Whereas, specific latent heat (equation Q=mL) is the amount of energy needed to change to the state of a substance either from solid to liquid, liquid to gas without changing its temperature.
An immersion heater can be wired in series to a joulemeter to measure the added heat to a material. Once a certain amount of energy (Eh) had been added the temperature change was recorded (Dt) Along with the mass the equation Eh=cmDt can be used to find out c which is the specific heat capacity. Physics Class 4.5 St. Davids High School, Dalkieth, Scotland
The equation we use in these calculations is q = smT, where q is the amount of energy, s is the specific heat capacity of the substance, m is its mass, and T the temperature change. The specific heat capacity of nickel is 0.440 J/g/deg C. If the temperature goes from 32 to 22 degrees C the nickel is being cooled, so energy will be released to the surroundings. q = 0.440 x 95.4 x 10 joules = 419.76 J This would usually be shown by using -10 deg C as the temperature change because it's going down. This gives an energy change of - 419.6 J, the negative sign being the convention for heat given out.
The equation for specific heat is: C = q/temp. change x mass. C is a substance's specific heat, which is a constant for every substance. q is its heat capacity in joules, temp. change is the change in temperature in degrees Celsius, and mass is in grams.
Here we use the equation ΔQ=mcΔT, where ΔQ is the energy change of the system, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the temperature change of the system. It can be rearranged to get c as the subject:c=(ΔQ)/(mΔT)Putting your known values into this equation yields an answer of 118Jg-1K-1.
Here we use the equation ΔQ=mcΔT, where ΔQ is the energy change of the system, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the temperature change of the system. It can be rearranged to get c as the subject:c=(ΔQ)/(mΔT)Putting your known values into this equation yields an answer of 118Jg-1K-1.
Q = mc(delta)T Q = quantity of heat energy m = mass c = specific heat capacity different constant for each different substance (delta)T = difference in temperature (subtract high temp - low temp)
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Specific heat capacity is the amount of energy or heat (q) required to raise the temperature of 1 gram of substance 1 degree Celsius. from the equation q = mc(Tf-Ti) q = energy / heat and is in joules (J) m = mass of in grams (look at periodic table for mass (g) per 1 mole of element) c = specific heat, for example water is 4.184 J/g*C Tf = Final temperature in *C Ti = Initial Temperature in *C
H = m s t H - heat energy in joule m- mass of the body in kg s - specific heat capacity J / kg / K t - the temperature difference may be a rise or fall in K
Quantity of Energy= mass x temperature change x specific heat capacity For example: Find the amount of energy needed to raise the temperature of 0.20 kg of lead by 15 degree Celsius if the specific heat capacity of lead is 0.90 J/g degree Celsius. Answer: J=200g x 15 degree Celsius x 0.90 J/g degree Celsius = 2700 J
Its 900 joules to raise the temperature of 1Kg of the substance by a degree, and we have 2Kg, to heat out sample we need 1800 J to raise the temperature by one degree celsius. we need to heat the sample by 40 degrees and if we need 1800 J per degree then 40 x 1800 = 72000 J needed. Or 72KJ
The equation Q=mcΔ t calculates the amount of energy for a body of mass to raise a unit temperature per unit mass. The specific heat capacity of water is 4.19 J/g°C which means that it takes 4.19 J to raise 1 g of water to 1°. The specific heat capacity also depends on what the surrounding temperature is. 4.19 J/g°C is the specific heat capacity at room temperature. Since temperature is the measurement of the average kinetic energy of the particles, the motion of particles in water affects the specific heat capacity which ultimately affects how much energy is needed to heat up water.
The specific heat of the substance being heated.
For an approximate calculation: specific heat capacity for water = 4.18 J/(g*degC) (how much energy is required per gram per change in degrees C) mass = 25g Change in temperature = 60-10 = 50 degC energy required = mass * change in temperature * specific heat capacity = 25g * 50 degC * 4.18 J/(g*degC)