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3440 kJ - Ape
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How much energy is required to vaporize 2 kg of gold Use the table below and this equation?
The heat of vaporization of gold is 158 kJ/kg. To find the total energy required to vaporize 2 kg of gold, you can use the equation: Energy = mass * heat of vaporization. Substitute the values to get: Energy = 2 kg * 158 kJ/kg = 316 kJ. Therefore, 316 kJ of energy is required to vaporize 2 kg of gold.
How much energy of is required to vaporize 1.5 kg of aluminum?
1650kj
How much energy is needed to vaporize 2 kg of gold?
The energy required to vaporize a material can be calculated using its heat of vaporization. For gold, the heat of vaporization is approximately 330 kJ/mol. Since gold has a molar mass of 196.97 g/mol, 2 kg of gold is equal to 10.15 moles. Therefore, the energy needed to vaporize 2 kg of gold is approximately 3.35 MJ.
How much energy is required to vaporized 2 kg of copper?
9460 kJ
How much energy is required to vaporize 1.5 kg of aluminum apex answer.com?
The energy required to vaporize 1.5 kg of aluminum can be calculated using the formula: energy = mass * heat of vaporization. The heat of vaporization for aluminum is around 10,000 J/g. So, the energy required would be 1.5 kg * 10,000 J/g = 15,000,000 J or 15,000 kJ.
How much energy is required to vaporize 2 kg of gold with this equation q ml vapor?
To vaporize gold, we need to consider its molar enthalpy of vaporization. The molar enthalpy of vaporization of gold is approximately 334 kJ/mol. Since the molar mass of gold is about 197 g/mol, vaporizing 2 kg (2000 g) of gold requires: ( q = \frac{2000 , \text{g}}{197 , \text{g/mol}} \times 334 , \text{kJ/mol} \approx 3,385 , \text{kJ}. ) Thus, approximately 3,385 kJ of energy is required to vaporize 2 kg of gold.
How much energy is required to vaporize 1.5 of aluminum?
1650kj
How much energy is required to evaporate 5 grams toluene?
Toluene had heat of vaporization of 38.06 kJ/mol Toluene molecular mass is 92.14 g/mol You just need to convert heat of vaporization into kJ/g basis and multiply your 5 gram to get the required amount of heat.
How much energy is required to vaporize 1.5 kg of aluminum (refer to table of latent heat values.)?
To calculate the energy required to vaporize 1.5 kg of aluminum, we need to use the latent heat of vaporization for aluminum, which is approximately 10,900 J/kg. The energy required can be calculated using the formula: Energy = mass × latent heat of vaporization. Thus, for 1.5 kg of aluminum: Energy = 1.5 kg × 10,900 J/kg = 16,350 J. Therefore, 16,350 joules of energy is required to vaporize 1.5 kg of aluminum.
How much energy is required to melt 1.5 kg of gold?
The heat of fusion for gold is 64.4 kJ/mol. To convert this to energy required to melt 1.5 kg of gold, we need to calculate the number of moles in 1.5 kg of gold (1.5 kg of gold is approximately 0.047 moles). Then, the energy required would be approximately 3.03 kJ.
How much energy is required to melt 2kg of gold?
To melt 2 kg of gold, it would require approximately 66,190 Joules per gram. Therefore, for 2 kg of gold, the total energy required would be around 132,380,000 Joules.
How much is required to vaporize 2 kg of copper?
9460 kJ
