Water has a specific heat of 1 calorie per gram per degree. This means that in order to raise 28.4 grams of water by 1 degree Celsius, it takes 28.4 calories. At an increase of 44.6 degrees Celsius, this equates to 1,266.64 calories of heat.
q(Joules) = mass * specific heat * change in temp.
q = 32.0 grams H2O * 4.180 J/gC *n (80.0 C - 25.0 C)
= 7230.08 Joules
7230.08 Joules (1 calorie/4.184 Joules)
= 1728 calories
The total amount of heat is the same as the energy. Because no phase change is occurring, use the formula Q = mc(delta)T. Q is the energy, m is the mass, c is the specific heat capacity of water as a liquid, and (delta)T is the change in temperature. So: Q = (100.0 g)(4.186 J/g°C)(15°C); Q = 6279 Joules.
I work in joules, so a conversion at the end.
q(joules) = mass * specific heat * change in temperature
q = (65 grams water)(4.180 J/gC)(40o C - 25o C)
= 4075.5 joules (1 calorie/4.184 joules)
= 974 calories
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q = C x m x (Tf-Ti), where q is heat, C is specific heat, and (Tf-Ti) is change in temperature.
CH2O(l) = 4.184 J/goC
(Tf-Ti) = 45oC-30oC = 15oC
massH2O = 100.0g
q = 4.184 J/goC x 100.0g x 15oC = 6300J (rounded to two significant figures)
Use,
q(joules) = mass * specific heat * change in temperature
q = (10 grams water)(4.180 J/g C)(40o C - 20o C)
= 836 joules
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The necessary heat is 15 calories (62,802 Joules).
ewfewf fw
When gypsum is heated to 120o C, it tuns into plaster of paris, after loosing about 75% of its water.
20 degrees Celsius is a temperature or a temperature range on the Celsius scale, where 0 is the freezing point of water and 100 is the boiling point of water. If the air temperature is 20 degrees Celsius, the weather is cool but not cold. If a pot of water is raised in temperature by 20 degrees Celsius it is heated by a set amount. 20 degrees Celsius is the same as 68 degrees Fahrenheit.
Gas? Nearly there. Its actually called water vapour. In industrial situations it would be called steam.
As temperature increases, the ability for water to absorb CO2 decreases. That is why we see higher CO2 when temperature rises in our atmosphere.
I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
The number of calories required will depend on the mass of water which is to be heated.
100 degrees celsius
I don't think you actually put calories into the water. You would dissipate thermal energy that could be measured in kCal or calories to heat the water. You may be thinking of the stored thermal energy from the heated water.
1,000 m
100 degree Celsius
it will boil once it reaches 100 degrees Celsius
12.775 kcal
There are 1000 g in one liter Use the formula Q=mc(delta)T Q=1200g(1calorie/g degrees celsius)(70 degrees - 20 degrees) Q=60,000 calories Q=60 kilocalories
All liquids expand when heated. e.g. Mercury in a thermometer. One exception may be water when heated form 0 to 4 degrees Celsius.
Its density decreases.
there are no calories in water you idiot
It take 4.2 Joules to raise 1 gram of water by 1 degree Celsius. Each gram of water is heated by 1.26 Joules, creating an increase in temperature of .3 degrees Celsius.