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How much iron is required to react with 48.0 grams of sulfur in the reaction 2Fe plus 3S yields Fe2S3?
Wiki User
∙ 13y ago
2Fe + 3S >> Fe2S3
48.0 grams S (1 mole S/32.07 g)(2 Fe/3 mole S)(55.85 g/1 mole Fe)
= 55 .7 grams of iron needed
Wiki User
∙ 13y ago
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In the reaction 2 Fe plus 3 S--- Fe2S3 how much iron is required to react with 48.0 g of sulfur?
55,73 g of iron
What is the chemical formula for ferrous disulfide?
ferric indicates the iron is +3 as opposed to +2 for ferrous sulfide indicates that there is sulfur with a -2 charge the formula is Fe2S3 two iron ions with a +3 = +6 3 sulfur ions with a -2 = -6 -6+6 = 0
Formula for iron iii sulfide?
These are the ions and their charges: Fe+3 SO3-2The charges have to add up to zero, so two +3 iron ions cancel out three -2 sulfite:Fe+3 Fe+3 SO3-2 SO3-2 SO3-2Simplify: Fe2(SO3)3
How does iron form?
If you're talking about Iron (II) Sulfide, where the oxidation of Iron is 2+, 2 electrons from the Iron atom is transferred to the Sulfur atom, producing Fe2+ and S2- .
What is the chemical formula for iron sulfate?
The chemical formula is... Fe2S3
In the reaction 2 Fe plus 3 S--- Fe2S3 how much iron is required to react with 48.0 g of sulfur?
55,73 g of iron
Why the mixture of the metal fillings and sulfur becomes chemical change when heat was applied?
When heat is applied to the mixture of metal fillings and sulfur, a chemical reaction occurs. The heat provides the energy necessary for the atoms of the metal and sulfur to rearrange and form new chemical bonds, resulting in the formation of a new substance with different properties than the original components. This process is called a chemical change, where the original substances react to form different compounds.
Metallic Iron was heated with solid sulfur to form a single solid sulphate what is the balanced chemical reaction?
The balanced chemical reaction for the formation of iron(II) sulfate from metallic iron and solid sulfur is: 3 Fe(s) + 3 S(s) → Fe2(SO4)3(s)
What type of reaction is Fe2S3 equals 2Fe plus 3S?
decomposition
Chemical formula For Ironite Trisulfide?
The chemical formula for ironite trisulfide is Fe2S3. It consists of two iron (Fe) atoms and three sulfur (S) atoms.
How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 2.75 g of Fe2S3 if the percent yield for the reaction is 65.0 percent?
.2M x V FeCl3=moles FeCl3 x 1mole Fe2S3/2mole FeCl3=moles of Fe2S3 x mm of Fe2S3/1 mole Fe2S3= g Fe2S3 x .65% yield. 2.75g Fe2S3/ .65= 4.23g Fe2S3/ 207.91= .02035 x 2mole FeCl3=.0407 moles FeCl3/ .2M FeCl3= .2035 L x 1000= 203.5 ml
What is the chemical formula for ferrous disulfide?
ferric indicates the iron is +3 as opposed to +2 for ferrous sulfide indicates that there is sulfur with a -2 charge the formula is Fe2S3 two iron ions with a +3 = +6 3 sulfur ions with a -2 = -6 -6+6 = 0
What is the formula for iron IIIsulfide?
Iron has a charge of +3 and Sulfur has a charge of -2, so iron III sulfide is: Fe2S3
How many grams of Fe2S3 can be formed from 17 g S and excess of Fe?
To calculate the maximum amount of Fe2S3 that can be formed, we need to determine the limiting reactant. Using the balanced equation for the reaction between Fe and S to form Fe2S3, we find that 8 moles of S react with 3 moles of Fe. From 17 g of S, we can calculate the amount of Fe2S3 that can be formed by converting the mass of S to moles and using the mole ratio from the balanced equation.
Is sulfur and iron an element or a compound or a mixture?
Sulfur and iron are both elements. An element is a pure substance that cannot be broken down into simpler substances through chemical reactions. Sulfur and iron are classified as elements based on their chemical properties.
What is n factor in terms of solution?
In cases of particular elements during reactions we see the change is their individual oxidation states.But if we have to calculate the equivalent weight of a species in a particular reaction,we have to find out the n factor for that particular species in the reaction.It is basically the overall exchange of electrons of a species per mole of that species in the reaction. And 1 thing more,n factor can never be calculated for individual atoms. For example:if we have to find out the equivalent weight of Fe2S3 in the reaction Fe2S3 --> FeSO4 + SO2 First v balance the equation which gives Fe2S3 + 502-->2FeSO4 +SO2 Then v find out the oxiadation states of S in d differsnt compounds cos v c that S is the only common element in all.In Fe2S3 The ox.state of s is -2.In FeS04 it's +6 n in SO2 it's +4. So we c the net exchange of electrons per mole of Fe2S3 in d reaction is 2*(+6-(-2))+(4-(-2)) = (2*8)+6 =22 Therefore the n factor of Fe2S3 is 22. So its equivalent weight will be Molecular weight/22.
Why the reaction of iron with sulfur produce ferrous sulphide not ferric?
Iron reacts with sulfur to form ferrous sulfide (FeS) instead of ferric sulfide (Fe2S3) because iron(II) ions (Fe2+) have a lower oxidation state compared to iron(III) ions (Fe3+). In this reaction, iron gains two electrons to form Fe2+ ions, which then combine with sulfide ions to form ferrous sulfide.
