Impossible to answer without at least knowing the manufacturer and model... sales@countrygunsmith.net
45 degrees
To work out the angle of any 'perfect shape' you use this formula: interior angle =((number of sides - 2) x 180)/ number of sides for an octagon: interior angle =((8-2) x 180 )/ 8 = 135 degrees
It would be worth somewhere between $65-$75
I will use caliber in TWO sentences: 1- The position of lead chemist would be perfect for someone of your caliber. 2- The sniper asked HQ to send more 50 caliber rounds; he is almost out of ammunition.
In perfect condition, $100.00
Yes, Snip isosceles right triangles off of the four corners of the square. Measure in from each corner 10/(2+sqrt(2)) inches. You will have a perfect octagon measuring 10/(1+sqrt(2)) inches per side.
200 USD
Around $100.
Yes - because, when you lay regular octagons together so they're touching, the space between the octagons is a perfect square.
50-300 USD or so
A pentagon has five equal sides an octagon has eight equal sides. Look at a stop sign, that is an octagon, a hexagon has has six equal sides. Try google image search for examples. Draw a perfect five pointed star, with equal distant sides and angles, then connect the points of the star with lines, if it is a perfect drawing your star should now be surrounded by a five equal sided shape called a pentagon.
The Crosman 1300 Medalist II was made between 1970-1976 as a .177 caliber and the model 1322 medalist was made from 1977-2000 as a .22 caliber. It is no longer in production. One in perfect condition will cost you around $80 plus if you can find one.