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Q: How much joules would it take to heat 40 g of ice at -50 c to steam at 125 c?
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How much heat is released when 12.4 g of steam at 100 degrees celsius condenses to water at 100 degrees celsius?

The latent heat of condensation of steam is 2260 Joules per gram (539.3 cals/g). So the amount of heat released by 12.4 g = 12.4*2260 Joules = 28,024 Joules or 6687 cals.


How many joules of energy are necessary to heat the steam from 100.0 degree c to 114.0 degree c?

That completely depends on how much steam there is. (mass)


How much heat energy will be required to lower the temperature of 2.67kg of steam from 282 degrees Celsius to 105 degrees Celsius?

You mean how much heat energy will be lost/transferred as you are losing Joules here. All in steam, so a simple q problem and no change of state. 2.67 kg = 2670 grams q = (2670 grams steam)(2.0 J/gC)(105 C - 282 C) = - 9.45 X 105 Joules ----------------------------------- This much heat energy must be lost to lower the temperature of the steam.


How much heat is generated by 1700 joules of work?

If all 1700 Joules of work get converted into heat, then, of course, you get 1700 Joules of heat.


How much energy must be supplied to turn 1 gram of water at 100 degrees centigrade to steam at 100 degree centigrade?

Heat of vaporization of water is 2.26 x 106 joules per kg. Therefore 1 gram of water will need 2.26 x 103 joules.


Measure of how much heat energy something contains?

It is measured in joules (J)


How much heat does it take to raise the temperature of 0.10 kg of gold by 25 oc?

About 322.5 Joules of heat


How much heat is in 1000 watts?

1,000 joules of heat energy for every second that the 1,000 watts' dissipation continues.


How much energy is needed to change 1 gram of ice to 1 gram of steam?

Assuming atmospheric pressure, ice of 0oC and steam of 100oC? This equals the heat of fusion + the specific heat of water * 100 + the heat of vaporization At 1 bar (rougly 1 atm): heat of fusion = 333.55 j/g specific heat = 4.186 j/(g*k) * 100 = 418.6 j/g heat of vaporization = 2257 j/g So 333.55 + 418.6 + 2257 = 3009.15 joules required.


The specific heat of gold is 0.131 Joules per gram. Celsius How much energy is required to heat 1.3 grams of gold from 25 Celsius to 46 Celsius?

0.131 joules/gram'C x 1.3 grams x (46-25)'C = 3.5763 joules


How much energy is required to vaporize 2kg of water at 100c?

The latent heat for water to steam is 550 calories (2310 Joules) per gram. For 2 grammes, double these figures.


How much heat is requireto raise the temperatureof 5kilogramsof water by 1 kelvin?

5 joules