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1.31*.3=.393 mols NaCl.
This also equals .393(22.99+35.45)=22.97 g NaCl.
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How much of NaCl is in 1.84 L of 0.200 M NaCl Answer in units of mol.?
(1.84 L)(0.200 mol/L) = 0.368 moles NaCl
What is 8.44 mci l-131?
8.44 mci l-131 = -122.56
How much salt is saltwater?
The sea water contain approx. 35 g/L NaCl.
What is the molarity of a solution made by dissolving 58.44 g of NaCl in enough water to make 1.0 L of solution?
Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl
What is the molarity of a solution containing 117 grams of sodium chloride in enough water to make a 40.0 L solution?
[117(g NaCl) / 58.5(g NaCl/mol NaCl)] / 40.0(L solution) = [117/58.5]/40.0 = 2.00(mol NaCl) / 40.0(L) = 0.0500 mol NaCl / L solution = 0.0500 M
Why is 0.9 NaCl osmolarity 300 mOsmL calculations?
- 0,9 g/L NaCl equal to 0,154 moles - but because NaCl is dissociated in two ions in water the relation is 1 mol NaCl equal 2 osmol/L - and so 0,9 % NaCl equal 308 milliosmole/L
How much nacl is required for a 200 mM NaCl solution?
You need 58,44 mg of ultrapure NaCl; dissolve in demineralized water, at 20 0C, in a thermostat, using a class A volumetric flask of 1 L.
How could you make a 1.00M solution if you had a 2.00M solution of NaCl?
If we add 1 L of water to 1 L of 2 M NaCl solution will give 2 L of 1 M NaCl solution
How much NaCl is required for 100 mM NaCl solution?
For 100 mM NaCl solution in 1L: Formula weight: 58.44 g/L Answer: 5.844 g/L if you want in 500 mL---2.922 g if you want in 250 mL---1.461 g if you want in 100 mL---584.4 mg
What is the concentrate of 2M NaCl?
2M NaCl is a equivalent to a solution with 116,88 g NaCl in 1 L water.
How to calculate the percentage of NaCl to M and mOsm?
9 g/L NaCl = 0,9 g/100 mL = 0,154 moles/L = 300 mOsm/L
What is the molarity of NaCl concentration of blood?
This concentration is min. 150 mmoles/L NaCl.
