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The resistance of a lamp operating at 115 volts and using 0.25 amp of current is 460. The relationship I used is Ohm's law.
The higher voltage need more resistance, from the formula W = V2 / R. That means R = V2 / W. So 220 v 100 W is 484 ohms, while 115 v 100 W is 132¼ ohms.
Divide the watts by the volts, so 32 / 115 is the answer in amps.
Using Ohm's Law (E = I R) Voltage = Current x Resistance or switch around to get R = E / I: 115 volts / 8 Amperes = 14.375 Ohms The above is correct for DC current but is close enough to be used for AC current.
The formula you are looking for is W = Amps x Volts.
To determine how many amps are in 115 volts, you need to know the power (in watts) being used. The relationship between volts, amps, and watts is given by the formula: Watts = Volts × Amps. Therefore, to find the amps, you can rearrange the formula: Amps = Watts / Volts. For example, if you have a device that uses 1150 watts, you would have 10 amps at 115 volts (1150 watts ÷ 115 volts = 10 amps).
Ohms law will tell you watts equals volts times amps: 115 x 5 = 575
Each voltage has a range and devices rated in that range will all work . The 110 to 120 volts is one range of voltages. The 220 to 240 is another range of voltages. The reason there is a range of voltages is to help the utility company out. They are mandated to keep the voltages within a + or - 5% range of a set voltage. Because there are loads coming on line and loads dropping off line the voltage fluctuates. Using a base voltage of 115 and 230 volts means that the voltage can rise by 115 +5% = 121 volts and drop by 115 - 5% = 109 volts. In the 230 volt range the voltage can rise by 230 + 5% = 241 and drop by 230 - 5% = 219 volts. As you see they are still in the usable voltage ranges.
You get watts from volts x amps, so 115 x2.5 = 287.5 watts
To calculate the amperage, use the formula: Amperes = Watts / Volts. For this situation, it would be 4000 watts / 115 volts ≈ 34.78 amps.
You need a step-up transformer.
A: Take 115 volts and multiply by 2.82. The frequency does not matter but he voltage does