The resistance of a lamp operating at 115 volts and using 0.25 amp of current is 460. The relationship I used is Ohm's law.
To calculate amperes, you can use Ohm's Law: amperes = voltage ÷ resistance. Current is the flow of electric charge, measured in amperes, that passes through a conductor in a unit of time. You can measure current using an ammeter in a circuit.
Convert the current to amperes, then (using Ohm's Law), divide voltage by current.
amperes
A resistance of 3 ohms connected between the terminals of a 9-volt battery will result in a current of 3 Amperes. If the battery is one of those little ones with snaps on top, it may be able to produce 3 amperes of current for about 3 seconds before it rolls over and totally dies.
Using Ohm's Law (E = I R) Voltage = Current x Resistance or switch around to get R = E / I: 115 volts / 8 Amperes = 14.375 Ohms The above is correct for DC current but is close enough to be used for AC current.
Using Ohm's law V:IR .I:V/R..I:100/5-20...I-20ampere
The current flowing through the circuit can be calculated using Ohm's Law: I = V/R, where I is the current, V is the voltage (12 volts), and R is the resistance (25 ohms). Plugging in the values, the current would be 0.48 amperes.
Ohm's Law: Resistance is voltage divided by current 110 volts divided by 0.4 amperes is 275 ohms.
It looks as if you can use Ohm's Law to calculate this: V=IR (voltage = current x resistance).
The current through the wire can be calculated using Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). In this case, the current would be 90 volts divided by 30 ohms, which equals 3 amperes.
The power ( P ) in an electrical circuit can be calculated using Ohm's Law, which relates voltage ( V ), current ( I ), and resistance ( R ). The equation is given by ( P = I^2 R ), where ( P ) is the power in watts, ( I ) is the current in amperes, and ( R ) is the resistance in ohms. This formula shows that power is directly proportional to the square of the current multiplied by the resistance.
if you want to find the current (in amperes) through the resistor then connect a ammeter in series with the resistor.