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How much work does Paul's force do during a displacement of the crate that is 12.0 m?
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How is work done by a force measured when force is in direction of displacement?
Work = (force on an object) times (displacement of the object during the time the force is applied to it).
Work is the product of and an object's displacement?
It is a product of force and displacement: Work = force x displacement
What is the friction force if a crate is at rest on the surface and a horizontal force of 50N is applied to it?
For every action there is an equal and opposite reaction, so if you push on a crate, the crate pushes back with a normal force equal to the force exerted. Thus, expect a force of 50 N to push back at you. However, if you meant the normal force of the ground exerted on the box, then that would included the 50 N force and the weight of the crate.
How much work is done when a 100N force pushes a crate 5m across a factory floor?
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?
Friction force = -F The crate is at rest, so all forces must be balanced
How is work done by a force measured when force is in direction of displacement?
Work = (force on an object) times (displacement of the object during the time the force is applied to it).
A crate is at rest on the ground what force or forces are acting on the crate?
The weight of the crate is acting downward on the ground and the ground is exerting a force equal to the weight of the crate upward on the crate.
What force or forces are acting on the crate?
The weight of the crate is acting downward on the ground and the ground is exerting a force equal to the weight of the crate upward on the crate.
Work is the product of and an object's displacement?
It is a product of force and displacement: Work = force x displacement
The application of a force through a distance?
Work = Force * displacement if the displacement and the force are parallel - work is positive if force and displacement are in the same direction, negative if they have opposite direction. At an angle Work = Force * displacement * cos(θ) where θ is the angle between the force and displacement vectors.
What is the friction force if a crate is at rest on the surface and a horizontal force of 50N is applied to it?
For every action there is an equal and opposite reaction, so if you push on a crate, the crate pushes back with a normal force equal to the force exerted. Thus, expect a force of 50 N to push back at you. However, if you meant the normal force of the ground exerted on the box, then that would included the 50 N force and the weight of the crate.
How much work is done when a 100N force pushes a crate 5m across a factory floor?
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
Explain what is the negative sign in hook's law mean?
It means that the force is in a direction opposite to the displacement of the spring.It means that the force is in a direction opposite to the displacement of the spring.It means that the force is in a direction opposite to the displacement of the spring.It means that the force is in a direction opposite to the displacement of the spring.
A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?
Friction force = -F The crate is at rest, so all forces must be balanced
If force is 5 newton and displacement is zero then?
If what you want to do is calculate the work, you need to multiply the force times the displacement.
How do you find the angle in the work done?
You measure it. Depending on the information provided, you can also calculate it, for example using trigonometry. ======================== Work done= Force vector . Displacement vector=Force*displacement*cos a, where a is the angle between the force and the displacement. So you have the values of work force and displacement then you can do the cosine inverse of the ratio of work done to the product of the force and displacement. That will give you the angle.
If you apply a force of 220 N to the lever how much force is applied to lift the crate?
If the perpendicular distance from the point of application of the force to the fulcrum is x metres and the perpendicular distance from the crate to the fulcrum is y metres, then the force applied on the crate is 220*x/y N.
