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The weight of the crate is acting downward on the ground and the ground is exerting a force equal to the weight of the crate upward on the crate.

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A crate is at rest on the ground what force or forces are acting on the crate?

The weight of the crate is acting downward on the ground and the ground is exerting a force equal to the weight of the crate upward on the crate.


What is the net force acting on a sliding crate?

The net force on a sliding crate is the vector sum of all forces acting on the crate. It is the force that is causing the crate to accelerate or decelerate. If all forces are balanced, the net force will be zero and the crate will move at a constant velocity.


If you push a crate with a force of 100 N and it slides at a constant velocity how much is the friction acting on the crate?

If the crate is moving at a constant velocity, the friction force is equal in magnitude but opposite in direction to the pushing force, so it is also 100 N. This is because the two forces are balanced and there is no net force acting on the crate.


What do you have to do get forces acting on an object to get you net force?

a girl and a boy are pulling heavy crate at the same time with 10 units of force each . what is the net force acting on ythe object?


Pull horizontally on a crate with a force of 140 N and it slides across the floor in a dynamic equilibrium How much friction is acting on the crate?

If the crate isn't accelerating ... i.e. sliding at a constant speed, not speeding up or slowing down ...then the forces on it are balanced. The pseudo-force of friction is 140N in the direction opposite toits speed.


When you push on a crate with a force of 10n to the right and your frined pushes on the crtate with a force of 25 n to the left which way will the crate move and what is the net force of the crate?

The crate will move to the left because the force to the left (25N) is greater than the force to the right (10N). The net force acting on the crate is the difference between the two forces: 25N (left) - 10N (right) = 15N to the left.


What is the force of friction acting on a crate that slides across the floor?

The force of friction acting on a crate sliding across the floor is equal in magnitude but opposite in direction to the force applied to move the crate. It depends on the coefficient of friction between the crate and the floor, as well as the weight of the crate.


If we push a crate at a constant velocity how do we know how much friction acts on the crate compared to our pushing force?

If the crate is moving at a constant velocity, then the force of friction acting on the crate is equal in magnitude and opposite in direction to the force you are applying to push the crate. This means that the force you apply to push the crate is balancing out the force of friction acting against it. By measuring the force you are exerting and observing the constant velocity of the crate, you can infer the magnitude of the friction force.


A 1500 N crate is being pushed across a level floor at a constant speed. What will be the acceleration of the crate?

The acceleration of the crate will be zero since it is moving at a constant speed. This means that the net force acting on the crate is zero, so the forces pushing it forward are balanced by the forces resisting its motion.


What is the force of friction when a crate slides across the floor?

The force of friction when a crate slides across the floor is dependent on the coefficient of friction between the crate and the floor, as well as the normal force acting on the crate. The frictional force resists the motion of the crate and can be calculated using the equation: frictional force = coefficient of friction * normal force.


How is a crate suspended from a rope that is connected to a metal ring?

The crate is suspended from a rope that is connected to a metal ring by the force of gravity acting on the crate and the tension in the rope.


If a crate is stationary on an incline does it mean that it is in the state of equilibrium?

If a crate placed on an inclined plane is moving at constant velocity or not moving at all -- which is really a special case of constant velocity where the velocity is zero -- then the sum of the forces acting upon it is zero. We can say that it is in a state of equilibrium, where all forces acting upon it are in perfect balance and cancel themselves out. A free-body diagram is often used to represent a body and the forces acting upon it and helps us visualize the relationship of the vector forces. See this link: http://en.wikipedia.org/wiki/Free-body_diagram#Example