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For every action there is an equal and opposite reaction, so if you push on a crate, the crate pushes back with a normal force equal to the force exerted. Thus, expect a force of 50 N to push back at you. However, if you meant the normal force of the ground exerted on the box, then that would included the 50 N force and the weight of the crate.

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12y ago

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to determine the friction force acting on the crate.

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Q: What is the friction force if a crate is at rest on the surface and a horizontal force of 50N is applied to it?
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A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?

Friction force = -F The crate is at rest, so all forces must be balanced


What is the coefficient of kinetic friction between the 13.0kg wooden crate and the horizontal force of 31N of the floor?

.419 .419


A 40kg crate is at rest on a level surface if the coefficient of static friction between the crate and the surface is 0.69 what horizontal force is required to get the crate moving?

276 Newtons. Coefficient of static friction is a ratio between the force it takes to budge the object over the normal force (mass times gravity). So: 0.69 = Force / 400 N (40 kg times 10 m/s^2, the force of gravity). Solve for 276 N.


If you push a crate at constant velocity how do you know how much friction acts on the crate compared to your pushing force?

When an object moves at a constant velocity, all forces acting on it must add up to zero. In the case of the crate on a horizontal surface, where the pushing force is directly horizontal (not down and horizontal), then the human push force must be equal and opposite to the friction force. In the case where the plane is inclined and/or where the human force isn't directly along the surface, we need to know the angles, component-ize all forces (human push force, normal force, friction, and weight), balance forces in the direction perpendicular to the plane (so it will not sink through the plane), and balance forces parallel to the plane (if it is to move at a constant velocity).


What is acceleration if coefficient of kinetic friction is 0.15 and 730 N force is applied to 186 kg crate?

2.454731183m/s^2


If you push on a heavy crate to the right and it slides what is the direction of friction on the crate?

The direction of friction on the crate is opposite to the direction in which it is sliding. In this case, since you are pushing the crate to the right, the friction will act to the left in order to oppose the motion.


Suppose you exert a horizontal push on a crate that rests on a level floor and it doesn't move How much friction acts compared with your push?

If the crate doesn't move, then the forces on it are balanced, and they add up to zero.The force of friction is equal to the force of your push, and acts in the opposite direction.Neither you nor the friction does any work.Note that as long as this is going on, these statements are all true regardless of whetherthe floor is level or sloped.


Is a crate resting on a loading ramp an example of static friction or fluid friction?

me


A plane inclined at an angle 35 degrees from horizontal if the coefficient of static friction between the crate and the plane is 0.65 will the crate slide down the plane?

Is mgsinΘ > μmgcosΘ ? Is sinΘ > μ cosΘ ? Is sin35º > .65 cos35º Is .573 > .532 => Yes, so crate slides down the plane, no matter what the mass is or acceleration due to gravity


As you increase your push will friction on the crate increase also?

no


A crate is supported by two ropes one rope makes and angle of 46.33 degrees with the horizontal and has a tension of 89.6 pounds on it the other rope is horizontal find the weight of the crate?

weight of crate would be 226 lb...saw it in back of the book


A horizontal force of 100 N pushes a box across a floor at a constant speed. what is the force of friction acting on the box?

If the horizontal velocity is constant, then the horizontal acceleration is zero,and the net horizontal force is zero.But if you are saying that the body was in constant motion and after that the force was applied, then the body will acccelerate because of the force. The net force applied on the body would be equal to the force applied to it when the body was in constant motion as here the force is in direction of the motion and hence the angle will be 0 giving the value of cos 0º as 1. Hence there would be no reduction in the net force