For every action there is an equal and opposite reaction, so if you push on a crate, the crate pushes back with a normal force equal to the force exerted. Thus, expect a force of 50 N to push back at you. However, if you meant the normal force of the ground exerted on the box, then that would included the 50 N force and the weight of the crate.
The information given in the question is not enough
to determine the friction force acting on the crate.
Friction force = -F The crate is at rest, so all forces must be balanced
276 Newtons. Coefficient of static friction is a ratio between the force it takes to budge the object over the normal force (mass times gravity). So: 0.69 = Force / 400 N (40 kg times 10 m/s^2, the force of gravity). Solve for 276 N.
2.454731183m/s^2
Is mgsinΘ > μmgcosΘ ? Is sinΘ > μ cosΘ ? Is sin35º > .65 cos35º Is .573 > .532 => Yes, so crate slides down the plane, no matter what the mass is or acceleration due to gravity
no
Friction force = -F The crate is at rest, so all forces must be balanced
.419 .419
276 Newtons. Coefficient of static friction is a ratio between the force it takes to budge the object over the normal force (mass times gravity). So: 0.69 = Force / 400 N (40 kg times 10 m/s^2, the force of gravity). Solve for 276 N.
When an object moves at a constant velocity, all forces acting on it must add up to zero. In the case of the crate on a horizontal surface, where the pushing force is directly horizontal (not down and horizontal), then the human push force must be equal and opposite to the friction force. In the case where the plane is inclined and/or where the human force isn't directly along the surface, we need to know the angles, component-ize all forces (human push force, normal force, friction, and weight), balance forces in the direction perpendicular to the plane (so it will not sink through the plane), and balance forces parallel to the plane (if it is to move at a constant velocity).
2.454731183m/s^2
The direction of friction on the crate is opposite to the direction in which it is sliding. In this case, since you are pushing the crate to the right, the friction will act to the left in order to oppose the motion.
If the crate doesn't move, then the forces on it are balanced, and they add up to zero.The force of friction is equal to the force of your push, and acts in the opposite direction.Neither you nor the friction does any work.Note that as long as this is going on, these statements are all true regardless of whetherthe floor is level or sloped.
me
Is mgsinΘ > μmgcosΘ ? Is sinΘ > μ cosΘ ? Is sin35º > .65 cos35º Is .573 > .532 => Yes, so crate slides down the plane, no matter what the mass is or acceleration due to gravity
no
weight of crate would be 226 lb...saw it in back of the book
If the horizontal velocity is constant, then the horizontal acceleration is zero,and the net horizontal force is zero.But if you are saying that the body was in constant motion and after that the force was applied, then the body will acccelerate because of the force. The net force applied on the body would be equal to the force applied to it when the body was in constant motion as here the force is in direction of the motion and hence the angle will be 0 giving the value of cos 0º as 1. Hence there would be no reduction in the net force