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It is defined aste depression in freezing point of solution containing non-volatile solute.wen molality is equal to 1 and is caled molal depression constant i.e. Tf=kf . m
Uric acid is an entirely different compound than salt, so I do not see how there is an equivalence between the two.
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Molality = moles of solute / kilograms of solventm = 5.10 / 4.47m = 1.14 molal
You make a 0.1 Molal solution of Zn(NO3)2 by weighing 0.1 mole of the salt and dissolving it in 1 kg of water.
molal
Salt lowers the freezing point of water by the amount of molals of NaCl in the solution. 0°C - 1.86(°C / molal) (NaCl molal). This will find the new freezing point and if the energy is enough to bring salt water below this temperature and turn the solution into ice then the salt water will freeze.
It is defined aste depression in freezing point of solution containing non-volatile solute.wen molality is equal to 1 and is caled molal depression constant i.e. Tf=kf . m
yes
Uric acid is an entirely different compound than salt, so I do not see how there is an equivalence between the two.
The boiling point is 101 oC.
1.0 molal
The melting point of water is lowered by 1.85 degrees Celsius if 29.2 grams of salt are dissolved in each Kg of water (called a "0.5 molal solution" of salt). So normal saline, a 0.9 molal solution), is lowered juts less thantwice this or 3.33 deg C. So normal saline freezes at -3.33 deg C or 26 deg F.
The freezing point of solution is always less than that of the freezing point of the pure solvent. The freezing point of pure water is 0 (zero) degree celsius. The freezing point of the water decreases with the increase in the sugar concentration. for ex. a 10 grams of sugar when dissolved in 100 grams of water, the freezing point depression of -0.56 degree Celsius A 10 molal sucrose will bring about the depression in freezing point of water to about -20 degree celsius
Aprox. 830 g.
The freezing point of solution is always less than that of the freezing point of the pure solvent. The freezing point of pure water is 0 (zero) degree celsius. The freezing point of the water decreases with the increase in the sugar concentration. for ex. a 10 grams of sugar when dissolved in 100 grams of water, the freezing point depression of -0.56 degree Celsius A 10 molal sucrose will bring about the depression in freezing point of water to about -20 degree celsius
Moles of solute/ kg of solvent = 2 molal solution